All categories

3 years ago

Domain Range The above is ______

Mathematics

1 answer:

IRISSAK [1]3 years ago

5 0

Answer:

Function.

Domain: {-3, 5, 3, -5}

Range: {-6, 2, 1}

Step-by-step explanation:

The domain of the relation shown here is {-3, 5, 3, -5}. Note how each of these elements is linked to ONLY ONE value in the range {-6, 2, 1}. Because of that, we conclude that the table shown represents a function.

You might be interested in

First to answer gets brainliest

skad [1K]

Answer:

Step-by-step explanation:

Because you can't do -x+1 so it would be (1,0) and then you have x^2 +3x-4 which is (-5,6)

6 0

3 years ago

Question 1 of 10

Kobotan [32]

Answer:

A. x + 5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients
Factoring

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \frac{x^2 - 25}{x - 5}$

Step 2: Simplify

Factor: $\displaystyle \frac{(x - 5)(x + 5)}{x - 5}$
Divide: $\displaystyle x + 5$

7 0

3 years ago

Read 2 more answers

Hey! i’ll give brainliest please help.

S_A_V [24]

Answer:

A is

Step-by-step explanation:

6 0

3 years ago

I don't quite understand this problem: 6+√44/2 (or 6 plus the square root of 44 over 2). I know the answer is 3+√11 (3 plus the

Sonja [21]

Does 2 is included in the square root?
sq.rt (44/2) ? or (sq.rt 44)/2

5 0

3 years ago

30+ Points!!! 5. Solve the following inequalities. a) 2 log3x – 2 logx3 -3 <0

Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

$\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}$

$2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)$

$\mathrm{Simplify}$

$-2logx^3-3$

$\mathrm{Add\:}3\mathrm{\:to\:both\:sides}$

$-2logx^3-3+3$

$\mathrm{Simplify}$

$-2logx^3$

$Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

$\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)$

$\mathrm{Simplify}$

$2lx^3og>2\log ^3\left(x\right)-3$

$\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0$

$\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\$

$\mathrm{Simplify}$

$g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0$

Step-by-step explanation:

6 0

3 years ago