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n200080 [17]
3 years ago
14

Domain Range The above is ______

Mathematics
1 answer:
IRISSAK [1]3 years ago
5 0

Answer:

Function.  

Domain:   {-3, 5, 3, -5}

Range:  {-6, 2, 1}

Step-by-step explanation:

The domain of the relation shown here is {-3, 5, 3, -5}.  Note how each of these elements is linked to ONLY ONE value in the range {-6, 2, 1}.  Because of that, we conclude that the table shown represents a function.

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First to answer gets brainliest
skad [1K]

Answer:

Step-by-step explanation:

Because you can't do -x+1 so it would be (1,0) and then you have x^2 +3x-4 which is (-5,6)

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3 years ago
Question 1 of 10
Kobotan [32]

Answer:

A. x + 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \frac{x^2 - 25}{x - 5}

<u>Step 2: Simplify</u>

  1. Factor:                                                                                                               \displaystyle \frac{(x - 5)(x + 5)}{x - 5}
  2. Divide:                                                                                                            \displaystyle x + 5
7 0
3 years ago
Read 2 more answers
Hey! i’ll give brainliest please help.
S_A_V [24]

Answer:

A is

Step-by-step explanation:

6 0
3 years ago
I don't quite understand this problem: 6+√44/2 (or 6 plus the square root of 44 over 2). I know the answer is 3+√11 (3 plus the
Sonja [21]
Does 2 is included in the square root?
sq.rt (44/2) ? or (sq.rt 44)/2
5 0
3 years ago
30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 &lt;0
Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

-2logx^3-3

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

-2logx^3-3+3

\mathrm{Simplify}

-2logx^3

Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

6 0
3 years ago
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