A box of colored crayons contains 11 distinct colors. In how many ways can 2 colors be chosen, assuming that the order of the co
lors chosen doesn’t matter? (If necessary consult a list of formulas.)
2 answers:
Answer:
55
Step-by-step explanation:
The first crayon is chosen out of 11,so there are 11 choices
11
The second crayon is chosen out of 10 crayons left so there are 10 choices
10
11*10 = 110
But we do not care about the order, so we divide by 2 since there are 2 places
110/2 =55
Answer:
55
Step-by-step explanation:
Equation is a = n * (n-1)
11 * 10 = 110
Order doesn't matter, and two colors, so divide by 2.
110/2 = 55
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Answer:
8%
Step-by-step explanation:
Given that:
Reliability of each = 0.92
r = 0.92
1 - (1 - r)(1 - r) = 1 - (0.08)(0.08) = 1 - 0.0064 = 0.9936
Percentage improvement :
1 - (0.9936) / r
1 - (0.9936 / 0.92)
1 - 1.08
= - 0.08
= 0.08 / 100 = 8%
2:1 is the ratio
- Rach :)
Answer:
y=2.5
Step-by-step explanation:
The 8th term is 33 and I don't think any of the options are there
I think it's B. The sum of angles in a triangle is always 180 degrees.
