A box of colored crayons contains 11 distinct colors. In how many ways can 2 colors be chosen, assuming that the order of the co
lors chosen doesn’t matter? (If necessary consult a list of formulas.)
2 answers:
Answer:
55
Step-by-step explanation:
The first crayon is chosen out of 11,so there are 11 choices
11
The second crayon is chosen out of 10 crayons left so there are 10 choices
10
11*10 = 110
But we do not care about the order, so we divide by 2 since there are 2 places
110/2 =55
Answer:
55
Step-by-step explanation:
Equation is a = n * (n-1)
11 * 10 = 110
Order doesn't matter, and two colors, so divide by 2.
110/2 = 55
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Step-by-step explanation:
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The first picture is for number 1 and the second one for number 2.
Answer:I think it’s 7/20
Step-by-step explanation:
We can create a formula first.
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840= 357+x
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