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2 years ago

What does 10a-a-a-a equal

Mathematics

1 answer:

balu736 [363]2 years ago

5 0

Simplifies into
10a-3a
Which equals
7a

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WILL MARK BRAINIEST PLS ANSWERRRRRR

Dahasolnce [82]

The answer would be the top one and the 3rd one

5 0

3 years ago

X - (2x + 1) = 8 - (3x + 3)<br><br> Ayuda porfa

Marina86 [1]

Answer:

x = 3

Step-by-step explanation:

cambia los signos : x - 2x-1=8-3x-3

like terms : -x-1=5-3x

variable: -x+3x=5+1 --> 2x=6

dividir: x=3

4 0

2 years ago

AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A

Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

$\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}$ .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

$\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}$ ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

$\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}$ .....(3)

The area of triangle APM is 35m².

$\text{Area of }\triangle APM=\frac{x}{4}$

$35=\frac{x}{4}$

$x=140$

Therefore the area of triangle ABC is 140m².

Using equation (2).

$\text{Area of }\triangle APC=\frac{x}{2}$

$\text{Area of }\triangle APC=\frac{140}{2}$

$\text{Area of }\triangle APC=70$

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

$\triangle BPC=\triangle BPM+\triangle PMC$

$70=35+\triangle PMC$

$35=\triangle PMC$

Therefore the area of triangle PMC is 35m².

8 0

3 years ago

yaroslaw [1]

Center c and a scale factor of 2

8 0

2 years ago

Read 2 more answers

A rectangular vegetable patch has an area of 56 square meters and a

vredina [299]

Answer:

The dimensions of the vegetable patch is 8 m by 7 m.

Step-by-step explanation:

Area of a vegetable patch is 56 square meters and the perimeter is 30 m.

If l is length and b is breadth, then area and perimeter of a rectangle is given by :

$A=l\times b$

$P=2(l+b)$

Substituting the values in the above formulas as :

$l\times b=56\ ....(1)$

and

$2(l+b)=30\\\\l+b=15\ .....(2)$

We need to solve equation (1) and (2) to find the values of l and b such that :

Equation (2), l = 15 - b

Equation (1) becomes,

$(15-b)b=56\\\\b=7\ m, 8\ m$

If b = 7 m, so, l = 8 m

If b = 8 m, l = 7 m

So, the dimensions of the vegetable patch is 8 m by 7 m.

4 0

2 years ago