Can someone please answer this???

Solve for r: d=2r d please hepl me

Luba_88 [7]

R=d/2 is the answer to this

6 0

4 years ago

Read 2 more answers

Which description describes the solutions to this inequality? q>52

Sophie [7]

Answer:

all the positive numbers that are larger than twenty-five

Step-by-step explanation: MAR ME BRAINLIEST PLEASE

hope this helps

5 0

3 years ago

When it is operating properly, a chemical plant has a daily production rate that is normally distributed with a mean of 885 tons

-BARSIC- [3]

Answer:

The test statistic Z = 1.844 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

Yes he is right

The manager claims that at least 95 % probability that the plant is operating properly

Step-by-step explanation:

Explanation:-

Given data Population mean

μ = 885 tons /day

Given random sample size

n = 60

mean of the sample

x⁻ = 875 tons/day

The standard deviation of the Population

σ = 42 tons/day

Null hypothesis:- H₀: The manager claims that at least 95 % probability that the plant is operating properly

Alternative Hypothesis :H₁: The manager do not claims that at least 95 % probability that the plant is operating properly

Level of significance = 0.05

The test statistic

$Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{875 -885}{\frac{42}{\sqrt{60} } }$

$Z = \frac{-10}{5.422} = -1.844$

|Z| = |-1.844| = 1.844

The tabulated value

$Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96$

The calculated value Z = 1.844 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

Conclusion:-

The manager claims that at least 95 % probability that the plant is operating properly

8 0

3 years ago

An individual receives a iq score of 73. taking into account standard error of measurement (sem), what is his "true score" 95 pe

ahrayia [7]

It's saying that 95% of the time the comparison from test to retest is 96% reliable.

so I would take (0.95+0.96)÷2= 0.955

then 73×0.955=69.715

then 73-69.715=3.285

so I would range the possible true score between 69.715 and 76.285

also written as 73 ± 3.285

6 0

3 years ago

The sum of the numbers from 1 to n can be performed recursively as follows: The sum from 1 to 1 is 1. The sum from 1 to n is n m

pogonyaev

Answer:

S(1) = 1

S(n) = S(n-1) + n

Where S(n) is the sum from 1 till n

And,

S(n-1) is the sum from 1 till n-1

4 0

3 years ago