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2 years ago

I put brainliest now can u help?

Mathematics

1 answer:

kramer2 years ago

6 0

Answer:

Check my previous answer but here you go:

Step-by-step explanation:

-Chetan K

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All real numbers between −14 and 14 inclusive

Vladimir79 [104]

Answer:

-13, -12, -11, -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13

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3 years ago

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2/3 * 1/2+ 3/4 /1+ 1/6

In-s [12.5K]

Answer:

2/3 * 1/2+ 3/4 /1+ 1/6 =1.25

1.25

Step-by-step explanation:

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2 years ago

A number divided by 5

viva [34]

10 or 25 and a lot more pretty much anything that ends with 0 or 5

6 0

3 years ago

I need an answer first and correct answer will give brainliest!!!! At summer camp, campers were asked to name their favorite spo

dexar [7]

15/100*x=39
x=39*100/15
x= 260 is the total number of people who were asked

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2 years ago

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Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago