Answer:
A- 462.86
Step-by-step explanation:
answered
There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Answer: 60 oranges
Step-by-step explanation:
<u>Given information</u>
Weight = 75 g / orange
Total = 4.5 kg
<u>Given formula</u>
Total = Number of oranges × Average weight
<u>Convert Kilogram unit to Gram</u>
1 kg = 1000 g
4.5 kg = 4.5 × 1000 = 4500 g
<u>Substitute values into the given formula</u>
Total = Number of oranges × Average weight
Number of oranges = Total / Average weight
Number of oranges = 4500 / 75
<u>Simplify by division</u>
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Answer:
(-6,-4)
Step-by-step explanation:
A reflection over the x-axis changes the y variable
(x,y)--->(x,-y)
2c=14 (move 5 to the other side by adding it to 9)
c=7 (divide by 2 to get c on its own)
