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3 years ago

Factor to write an equivalent expression.(What is the Greatest Common Factor?). −9x+15y

Mathematics

1 answer:

KengaRu [80]3 years ago

3 0

Answer:

GCF is 3

Step-by-step explanation:

Given the expression -9x + 15y

First, we need to find ther individual factors

-9x = -3 *3 * x

15y = 3 * 5 * y

Since 3 is common to both factors

−9x+15y = 3(-3x+5y)

Hence the GCF is 3

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Help please!!!!!!!!!

SOVA2 [1]

Find the area of the triangles and smal ler square and add them together ; and find the area of the complete square and set them equal to each other (these are known truths)
triangle: l×w /2
square: s^2
There are 4 triangles so

4 (1/2ab)+c^2= (a+b)(a+b)
simplify

2ab+c^2= a^2+2ab+b^2
-2ab both sides

c^2=a^2+b^2

tada!! it's proven :)

6 0

3 years ago

A firm produces 16,200 units at a total cost of $37,585.60. Find the cost per unit to the nearest cent.

Julli [10]

There are a total of 16 200 units with a total costs of 37 585.60 dollars. Now, Given with the choices for the answer, let's find out which one is correct. To be able to get the answer, simply divide the total costs, with the total number of units. => 37 585.60 dollars / 16 200 units => 2.3201 dollars per unit.Next, we need to round this cents to the nearest given options.Since the number next to hundredths is less than 5 , the let's round it to : => 2.32. - this is the correct answer.<span>
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3 0

2 years ago

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$