The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches
So, length of sides will be,
with the pythagorean theorem
using the formula of the quadratic equation
the length cannot be negative, therefore x=7
length of the shorter leg is: 7ft
length of the longer leg is: 3+3(7)= 24ft
length of the hypotenuse is: 4+3(7)= 25ft
Answer:
18 pitches.
Step-by-step explanation:
I'm assuming the "9 out of 15" is the fraction of pitches Tony hit at baseball practice.
Hence, Tony missed 6 out of 15 pitches.
6/15 * 45
= 6 * 3
= 18 pitches.
Hope this helped!
Infinite Solutions :) Dhdhsjsjdnnd
Answer:
k = 15
Step-by-step explanation:
∵ x² - 8x + k = 0 ⇒ has two roots x1 and x2
∵ ax² + bx + c = 0 has two roots
∴ The sum of roots = -b/a and the product of them = c/a
∵ a = 1 , b = -8 and c = k
∴ x1 + x2 = -(-8)/1 = 8
∴ x1 + x2 = 8 ⇒ (1)
∵ 3x1 + 4x2 = 29 ⇒ (2)
Multiply (1) by -4
∴ -4x1 - 4x2 = -32 ⇒ (3)
Add (2) and (3)
∴ -x1 = -3
∴ x1 = 3
By substituting value of x1 in (1)
∴ 3 + x2 = 8
∴ x2 = 5
∴ The roots are 3 and 5
∴ c/a = 3 × 5 = 15 ⇒ (a = 1)
∴ c = 15
∴ k = 15
