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alina1380 [7]
2 years ago
10

Greatest common factor of 30 and 75

Mathematics
2 answers:
asambeis [7]2 years ago
7 0

Step-by-step explanation:

The prime numbers 5 and 3 are both factors that are common to 30 and 75. The product of these factors is 3×5 = 15. Thus, the “Greatest Common Factor” of 30 and 75 is 15.

bekas [8.4K]2 years ago
3 0

Answer:

the Greatest common factor of 30 and 75 is 15

Step-by-step explanation:

The product of these factors is 3×5 = 15. Thus, the “Greatest Common Factor” of 30 and 75 is 15.

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What would be the circumference of a circle with a radius of 5?
lilavasa [31]

Answer: 10pi

Step-by-step explanation:

C = 2(pi)r

r = 5

2*(pi)*5 = C

10pi = C is the exact answer

If we make 3.14 for the pi substitution, then:

2*3.14*5=C

31.5 = C

4 0
2 years ago
Which expression is a simplified form of –10g – 4h^2 + 15g – 8h^2 – 4?
igomit [66]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

-12h^2+ 5g-4

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

-10g -4h^2+15g-8h^2-4\\------------------\\\rightarrow -10g+15g -4h^2-8h^2-4\\\\\rightarrow 5g - 12h^2 - 4\\\\\rightarrow \boxed{-12h^2+5g-4}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

8 0
2 years ago
Read 2 more answers
A savings account with an initial deposit of $10,000 has an annual interest rate of 3.2%. The interest on the account is compoun
makkiz [27]

Answer:

account balance will be $12113.9 and the interest is $2113.9.

7 0
2 years ago
Please help with question 15 and 16!!!
kykrilka [37]
15. [4] insufficient information. only given SA
16. There are 3 right triangles, 3 Pythagorean theorem equations 
x²+b²= 16²
12²+a² = x²
a²+4² = b²

combine equations using substitution to get in terms of only x
substitute b² for (a² +x²) in first equation
x²+a²+4²=16²
substitute a² for (x² - 12²)
x²+x²-12²+4² = 16²
solve for x
2x² - 144 + 16 = 256
2x² = 256 + 144 - 16
2x² = 384
x² = 384/2
x² = 192
x = 13.85

rounded to nearest tenth, x = 13.9




6 0
3 years ago
louise bought 80 metres of fencing to make an enclosure for her pet dog .tommy if louise expects a rectangular enclosure what is
OleMash [197]

Answer:

400 m^2.

Step-by-step explanation:

The largest  area is obtained where the enclosure is a square.

I think that's the right answer because a square is a special form of a rectangle.

So the square would be 20 * 20  = 400 m^2.

Proof:

Let the  sides of the rectangle be x and y m long

The area A = xy.

Also the perimeter  2x + 2y = 80

x + y = 40

y = 40 - x.

So substituting for y in A = xy:-

A = x(40 - x)

A = 40x - x^2

For maximum value of A  we find the derivative and equate it to 0:

derivative A' =  40 - 2x = 0

2x = 40

x = 20.

So y = 40 - x

= 40 - 20

=20  

x and y are the same value so x = y.

Therefore for maximum area the rectangle is a square.

3 0
2 years ago
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