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2 years ago

15

Does the tempurture of the vinegar affect the volcano flow

1 answer:

aleksandr82 [10.1K]2 years ago

6 0

The temperature of vinegar does increase the rate of reaction according to the collision theory.

Hope this answers your question!

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A child and her mother are at the park. The child walks around the rectangular park while her mom waits on a bench. The child re

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C 1,772 is the answer for the question

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3 years ago

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What is first and second element of the periodic table?

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The elements on the periodic table are listed in increasing atomic number.

Hydrogen is the first element, and has an A.N. of 1. Also, its very interesting how it doesn't need 8 valence electrons to be stable.

The second element is Helium, which has an A.N (atomic number) of two.

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Which cell structure is correctly paired with its primary function?

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3 years ago

Jane is sliding down a slide. What kind of motion is she demonstrating?

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10) How many grams are there in 1.00 x 10^24 molecules of BC13?

lana66690 [7]

194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

Explanation:

In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.

It is known that 1 moles of any element has 6.022×10²³ molecules.

Then 1 molecule will have $\frac{1}{6.022*10^{23} }$ moles.

So $1*10^{24} molecules = \frac{1*10^{24} }{6.022*10^{23} } =1.66 moles$

Thus, 1.66 moles are included in BCl₃.

Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.

As it is known as 1 mole contains molecular mass of the compound.

As the molecular mass of BCl₃ will be

$Molecular mass of BCl_{3}= Mass of Boron + (3*Mass of chlorine)$

Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.

Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.

$grams of BCl_{3}=Molar mass of BCl_{3}*Number of moles$

$grams of BCl_{3}=117.17*1.66=194.5 g$

So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

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3 years ago