Answer:
Zinc oxide is the antimicrobial in the medicated foot powder.
Explanation:
Zinc oxide (ZnO) is used to treat several skin conditions such as acne, dermatitis, eczema, etc because it has antibacterial and antifungal properties. This property of the ZnO depends on its size i.e., the smaller the size of ZnO, the stronger antimicrobial activity it has. So, the ZnO nanoparticles are more efficient.
The zinc oxide interacts with the sulfur atoms in microbial proteins and denatures them and destroys their function. This action completely inhibits microbial growth. The treatment with zinc oxide causes the reduced production of conidia in fungi, damages their hyphae and inhibits their ability to produce mycotoxins.
The compounds containing zinc such as ZnSO4, Zn(ClO4)2, etc also have antifungal and antimycotoxin properties that can cause changes in the fungi cell structure. Also, the free radicals formed on the surface of the ZnO nanoparticles can cause damage to the lipids in the bacterial cell membranes that can lead to the leakage and breakdown of the bacterial cell membranes.
0.0102 moles Na₂CO₃ = 1.08g of Na₂CO₃ is necessary to reach stoichiometric quantities with cacl2.
<h3>Explanation:</h3>
Based on the reaction
CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃
1 mole of CaCl₂ reacts per mole of Na₂CO₃
we have to calculate how many moles of CaCl2•2H2O are present in 1.50 g
- We must calculate the moles of CaCl2•2H2O using its molar mass (147.0146g/mol) in order to answer this issue.
- These moles, which are equal to moles of CaCl2 and moles of Na2CO3, are required to obtain stoichiometric amounts.
- Then, we must use the molar mass of Na2CO3 (105.99g/mol) to determine the mass:
<h3>
Moles CaCl₂.2H₂O:</h3>
1.50g * (1mol / 147.0146g) = 0.0102 moles CaCl₂.2H₂O = 0.0102moles CaCl₂
Moles Na₂CO₃:
0.0102 moles Na₂CO₃
Mass Na₂CO₃:
0.0102 moles * (105.99g / mol) = 1.08g of Na₂CO₃ are present
Therefore, we can conclude that 0.0102 moles Na₂CO₃ is necessary.to reach stoichiometric quantities with cacl2.
To learn more about stoichiometric quantities visit:
<h3>
brainly.com/question/28174111</h3>
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