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Rudik [331]
3 years ago
15

Is C2H2 + 2H2 ----- C2H6 a substitution reaction​

Chemistry
1 answer:
3241004551 [841]3 years ago
3 0

Answer:

No

Explanation:

No, this is an addition reaction

HC≡CH + 2H-H ----> H3C - CH3

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Which of the following is not a part of every scientific investigation?
Dmitry_Shevchenko [17]

Answer:

the correct answer is Group of answer choices

6 0
3 years ago
On a flight to Europe, you notice that the packages of peanuts are puffed up. Why? 1. The jet is over-pressurized at high altitu
hodyreva [135]

Answer:

The correct answer is;

5. They were packaged at a higher pressure on the ground, thus causing the gas inside the packages to expand in the sky where the jet is at a lower pressure.

Explanation:

According to Boyle's law, the pressure of a given mass of gas is inversely proportional to it volume at constant temperature

P₁·V₁ = P₂·V₂

At the factories, the peanuts are packaged at atmospheric conditions whereby P₁ = 1 atm, however, the pressure of the air in the atmosphere decreases with altitude as such the pressure in the airplane jet is about a fraction of hat on the ground by about a factor of 0.7.

Therefore P₂ = 0.7 atm and we have

V₂ = P₁·V₁/P₂ = 1 atm×V₁/0.7 atm = 1.43·V₁

The volume increases at high altitudes

7 0
3 years ago
PLSS HELP
-Dominant- [34]
Atoms (Sodium and Fluorine)
8 0
3 years ago
Read 2 more answers
Someone help 6th grade science i will give brainliest
patriot [66]
I believe the answer is C
3 0
3 years ago
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A piston chamber filled with ideal gas is kept in a constant-temperature bath at 25.0°C. The piston expands from 25.0 mL to 75.0
larisa [96]

Answer : The work done by the system is, 2.2722 J

Explanation :

The expression used for work done in reversible isothermal expansion will be,

w=nRT\ln (\frac{V_2}{V_1})

where,

w = work done = ?

n = number of moles of gas  = 0.00100 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = 25^oC=273+25=298K

V_1 = initial volume of gas  = 25 mL

V_2 = final volume of gas  = 75 mL

Now put all the given values in the above formula, we get:

w=0.00100mole\times 8.314J/moleK\times 298K\times \ln (\frac{75}{25})

w=2.722J

Therefore, the work done by the system is, 2.2722 J

8 0
3 years ago
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