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Rudik [331]
3 years ago
15

Is C2H2 + 2H2 ----- C2H6 a substitution reaction​

Chemistry
1 answer:
3241004551 [841]3 years ago
3 0

Answer:

No

Explanation:

No, this is an addition reaction

HC≡CH + 2H-H ----> H3C - CH3

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What is the main idea of the kinetic theory of heat?
Goshia [24]
 – liquids, solids or gases – are made up of atoms and molecules that are in constant motion.<span> The theory also states that collisions between atoms and molecules are elastic</span>
5 0
3 years ago
How carbon dioxide prepared in lab?
Nana76 [90]

Explanation:

In laboratory, carbon dioxide is not obtained from the air, carbon dioxide is prepared from carbonates by adding acids to the carbonates. In this experiment carbon dioxide is prepared by the reaction of marble with hydrochloric acid.

7 0
3 years ago
Identify the number of moles in 369 grams of calcium hydroxide. Use the periodic table and the polyatomic ion resource.
topjm [15]

Answer : The number of moles in 369 grams of calcium hydroxide is, 4.98 moles

Explanation : Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used :

\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}

Now put all the given values in this formula, we get the moles of calcium hydroxide.

\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole

Therefore, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

7 0
3 years ago
A clear liquid in an open container is allowed to evaporate. After three days, a solid is left in the container. Was the clear
Mashutka [201]

The liquid did not chemically bond after 3 days, therefor it is a mixture.

Hope this helps!

7 0
3 years ago
The decomposition of carbon disulfide to carbon monosulfide and sulfur is first order with k=2.8 ×10^-7 at 1000°C .What is the h
RoseWind [281]

Answer:

2.5×10⁶ s

Explanation:

From the question given above, the following data were obtained:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

The half-life of a first order reaction is given by:

Half-life (t½) = 0.693 / Rate constant (K)

t½ = 0.693 / K

With the above formula, we can obtain the half-life of the reaction as follow:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

t½ = 0.693 / K

t½ = 0.693 / 2.8×10¯⁷

t½ = 2.5×10⁶ s

Therefore, the half-life of the reaction is 2.5×10⁶ s

6 0
3 years ago
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