If a^2 + b^2 = c^2 then it is a right triangle.
22^2 + 26^2 ?=? 34^2
484 + 676 ?=? 1156
1160 ?=? 1156
This is NOT TRUE so it is not a right triangle.
(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0
Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)
sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º
The solutions when 0≤x≤360º are: 36.87º and 306.87º.
Answer:
4
Step-by-step explanation:
The y-coordinate of the point where both lines intersect will give us the same solution for x.
At y = 4, both equations will have a corresponding x-value of 1.
Therefore, the value of y that that will make both equations have the same solution of x is 4.
Answer:
area formula: base x height 9x4=36
Step-by-step explanation:
Answer:
Answer: First, we use Ohm's law ( V = I × R ), to find the current through the resistor. The voltage across the resistor is V = 9 V. The resistance of the resistor is R = 100 Ω. Then, we can use the power rule ( P = I × V ), to find the power dissipated by the resistor
Step-by-step explanation:
i dont know if its the right answer but here
