1/5 < 3/10 < 1/2 i believe thats it i hope this helped:)
Answer:
Terrence's
Step-by-step explanation:
The length of the square that will be cut out is the height of the box.
1. a
Anya's method: 8.5 -1.5 =7, 11- 1.5 =9.5, the height is 1.5, so the volume is height x length x width which is 1.5 x 9.5 x 7 =99.75 squared inches.
Terrence's method: 8.5-3 = 5.5, 11-3 = 8. Vol= 5.5 x 8 x 3 =132 squared inches. 99.75 < 132 squared inches, Terrence's idea would create larger volume.
1. b
The box's size depends on the length/width/height of the cardboard being cut, which is why different measurements / cutting methods for the same size cardboard can result in different box sizes.
2. The square would be cut from all four corners, therefore the sum of the 2 squares on the cardboard cannot exceed the short side of the cardboard. The shorter side of the cardboard is 8.5 inches, divided by 2 = 4.25 inches, hence the squares cannot be larger than 4.25 inches. Keep in mind that if you cut exactly 4.25 inches you will have a strip of 2.5 inches width that cannot be turned into a box.
If you want to cut 5 inches squares out, depending on how you draw it, it would either overlap or go outside of the paper because 5+5 is ten, surely on the 11 inches side that would still be perfectly fine but for the 8.5 inches side, there isn't any room for the 10 inches.
9514 1404 393
Answer:
(A) one solution: x = 3
(B) one solution: x = -10
(C) one solution: x = 4
Step-by-step explanation:
An equation will have one solution if it can be reduced to the form ...
ax +b = 0
It will have an infinite number of solutions if it reduces to the form ...
0 = 0
It will have no solution if it reduces to the form ...
1 = 0
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<h3>(A)</h3>
2x + 4 (x - 1) = 2 + 4x . . . . . . given
Subtract 2 +4x from both sides and simplify
2x -6 = 0 . . . . . . . . . . . . . . one solution (x=3)
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<h3>(B)</h3>
25 - x = 15 - (3x + 10)
Add 3x -5 to both sides and simplify
2x +20 = 0 . . . . . . . . . . . one solution (x=-10)
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<h3>(C)</h3>
4x = 2x + 2x + 5 (x - 4)
Subtract 4x from both sides and simplify
0 = 5x -20 . . . . . . . . . . one solution (x=4)
Setup 2 problems
2x - 7 < 15 and 2x - 7 > -15
2x < 22 2x > -8
x < 11 x > -4
Or you can write it -4 < x < 11
