Surface Area of a Sphere = 4π(d/2)²
Let the smaller sphere's diameter be just a sample of 4 units in diameter and let the large spheres diameter be 4 times that of the smaller sphere.
Small Sphere: 4π(4/2)² = 16π units²
Large Sphere: 4π(16/2)² = 256π units²
256π / 16π = 16 times
The large sphere has a surface area 16 times that of the smaller one.
Answer:
negative because since -90 and -5 are both negative just add and keep it the sign which is -95
hope this helps
have a good day :)
Step-by-step explanation:
Answer:
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<em><u>Thanks</u></em><em><u><</u></em><em><u>3</u></em>
<em><u>Life</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>short</u></em><em><u>,</u></em><em><u> </u></em><em><u>Smile</u></em><em><u> </u></em><em><u>while</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>still</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>teeth</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>
So to start 3*8=24 reams of paper
24 divided by 5=4.8
4.8*6=28.8 weeks.
It's up to you if you want to do 28 weeks or 29 weeks
Answer:
Correct choice is A
Step-by-step explanation:
Two vertices of the rectangle have coordinates A(-1, 5) and B(2, 1). If rectangle sides are parallel to the axes, then two remaining vertices have coordinates C(-1,1) and D(2,5) (see attached diagram for details).
Find the length and the width:
![AC=\sqrt{(-1-(-1))^2+(5-1)^2}=4\ units,\\ \\AD=\sqrt{(2-(-1))^2+(5-5)^2}=3\ units.](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7B%28-1-%28-1%29%29%5E2%2B%285-1%29%5E2%7D%3D4%5C%20units%2C%5C%5C%20%5C%5CAD%3D%5Csqrt%7B%282-%28-1%29%29%5E2%2B%285-5%29%5E2%7D%3D3%5C%20units.)
Then the length is 1 unit longer than the width.