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liraira [26]
3 years ago
15

What values of a make the equation have non real solution?

Mathematics
1 answer:
STALIN [3.7K]3 years ago
7 0
These can be some values of equation
6x+ 12=30

This question might not get the right answer but this how you set equations.






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Layla bought a pencil for $1.25, a pen for $2.25, and three erasers for $0.45 each. She gave the cashier $10 for the items. How
snow_lady [41]

Answer:

1.25+2.25+(o.45 x 3)

=6.95

10-6.95

= got back $3.05

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is equivalent to 2/5?
zhuklara [117]
As in decimal it would be 0.4 but if you want a fraction it could be 4/10

3 0
3 years ago
What is 2 1/4 as an improper fraction​
sattari [20]

Answer:

9/4

2 1/4= 9/4 because 2*4=8+1=9 9/4

7 0
3 years ago
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The asymptote of the function f(x) = 3x + 1 – 2 is ___. Its y-intercept is ___.
Svetradugi [14.3K]
The only way this could have an asymptote, either horizontal, vertical, or oblique is if it is a rational function, proper or improper. This function is linear:
y=3x-1 is what it simplifies to and it is a straight line through the y axis at -1 and has a positive slope of 3. There are no asymptotes here. But the y intercept, like I stated, is (0, -1)
8 0
3 years ago
If jobs arrive every 15 seconds on average, what is the probability of waiting more than 30 seconds?
Aleksandr [31]

Answer: 0.14

Step-by-step explanation:

Given: Mean : \lambda=15\text{ per seconds}

In minutes , Mean : \lambda=4\text{ per minute}

The exponential distribution function with parameter \lambda  is given by :-

f(t)=\lambda e^{-\lambda t}, \text{ for }x\geq0

The probability of waiting more than 30 seconds i.e. 0.5 minutes is given by the exponential function :-

P(X\geq0.5)=1-P(X\leq0.5)\\\\=1-\int^{0.5}_{0}4e^{-4t}dt\\\\=1-[-e^{-4t}]^{0.5}_{0}\\\\=1-(1-e^{-2})=1-0.86=0.14

Hence, the probability of waiting more than 30 seconds = 0.14

5 0
3 years ago
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