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3 years ago

PLEASE HELP!! Pleaseee

Mathematics

1 answer:

zhenek [66]3 years ago

6 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The given angles are forming alternate interior pair, so :

$4x - 2 = 3x + 6$

$4x - 3x = 6 + 2$

$x = 8$

hence, value of x = 8°

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Two number differ by 3 The sum of their reciporcal is 7/10 find tge numbers

motikmotik

The numbers are 5 and 2.

Reciprocals: 5- 5/10
2- 2/10
(2/10)+(5/10)= 7/10
5-2= 3

Answer: 5 and 2

6 0

3 years ago

Read 2 more answers

9.1(6)+8.7(7)=_+60.9 How do I solve this?

timurjin [86]

Answer:

The answer is 54.6.

9.1(6)+8.7(7)=54.6+60.9

Step-by-step explanation:

Given:

9.1(6)+8.7(7)=_+60.9

Now, to solve it:

9.1(6)+8.7(7)=_+60.9

Let the _be x.

So, we remove parenthesis first that makes it multiply with the number next to it:

$9.1\times 6+8.7\times 7=x+60.9$

$54.6+60.9=x+60.9$

Now adding on L.H.S:

$115.5=x+60.9$

Subtracting on both sides by 60.9 we get:

$54.6=x$

$x=54.6$

Therefore, the answer is 54.6.

7 0

4 years ago

Please please!!!! HELP

wlad13 [49]

Answer:

Part A: 38

Part B: 5 or 4 got two different answers

Part C: range because it tells how many numbers are involved apart from the smallest and largest

Step-by-step explanation:

Part A: highest number - lowest number

78-40

Part B

5 0

3 years ago

The sides of a right triangle measure 18 yd, 24 yd, and 30 yd. The two shortest sides of the triangle form its right angle. What

defon

Answer:

216 yd²

this is the right answer

mark as brainliest

6 0

3 years ago

A single 6-sided die is rolled twice. The set of 36 equally likely outcomes is {(1,1), (1,2), (1,3), (1,4), left parenthesis

Dennis_Churaev [7]

Answer:

The probability of getting two numbers whose sum is greater than 9 and less than 13 is $\frac{1}{6}$

Step-by-step explanation:

Given : A single 6-sided die is rolled twice.

To find : The probability of getting two numbers whose sum is greater than 9 and less than 13 ?

Solution :

The set of 36 equally likely outcomes,

1 2 3 4 5 6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Getting two numbers whose sum is greater than 9 and less than 13

The favorable outcome is (4,6),(5,5),(5,6),(6, 4),(6, 5),(6, 6) = 6

The probability is given by,

$\text{Probability}=\frac{\text{Favorable Outcome}}{\text{Total Outcome}}$

$\text{Probability}=\frac{6}{36}$

$\text{Probability}=\frac{1}{6}$

Therefore, The probability of getting two numbers whose sum is greater than 9 and less than 13 is $\frac{1}{6}$

5 0

4 years ago