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2 years ago

PLEASE HELP!! Pleaseee

Mathematics

1 answer:

zhenek [66]2 years ago

6 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The given angles are forming alternate interior pair, so :

$4x - 2 = 3x + 6$

$4x - 3x = 6 + 2$

$x = 8$

hence, value of x = 8°

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A triangular pyramid and its net are shown. Rain uses the calculations below to conclude

Fynjy0 [20]

Answer:

is correct, he determines it correctly, he solved it correctly, 238.5

Step-by-step explanation:

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3 years ago

Please I need actual help with these!!!! I will mark brainliest if right! Please don't answer if you don't know it!!(I will repo

MrMuchimi

Answer:

Step-by-step explanation:

first pic

Statement. Reasons

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second pic

statement. reason

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third pic

statement. reason

1. Already stated. 1. Already stated

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( hope this helps! )

3 0

2 years ago

Read 2 more answers

How to rename the number 24 ten thousands?

kifflom [539]

Its 24,000 if the number goes to ten thousand's place..

5 0

3 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

2 years ago

Select one:<br> a. 4<br> b.5<br> c. 6<br> d. 7

tino4ka555 [31]

Answer:

Step-by-step explanation:

Given 2 secants intersect a circle from a point outside the circle, then

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

x(x + 10 + x) = 6(6 + 10 + x)

x(2x + 10) = 6(16 + x) ← distribute parenthesis on both sides

2x² + 10x = 96 + 6x ← subtract 96 + 6x from both sides

2x² + 4x - 96 = 0 ← in standard form

Divide through by 2

x² + 2x - 48 = 0 ← factor the left side

(x + 8)(x - 6) = 0

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x - 6 = 0 ⇒ x = 6

However x > 0 ⇒ x = 6 → C

7 0

3 years ago