
The slope is 2
y=2x + b
Plug in a point to solve for b
8 = 2(3) + b
8 = 6 + b
b = 2
The equation is y = 2x + 2
Unusual notation. I won't fuss with it.
a. We have isosceles PRT, so angle RPT = angle RTP.
By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.
We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP
Similarly, m angle RPT = 2 m angle MPT
2 m angle MTP = 2 m angle MPT
angle MPT = angle MPT
That's the first part.
b. That makes MPT isosceles.
c. 2x+124=180
2x = 56
x = 28 degrees
MTP = 28 degrees
d. We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees
PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees
Bad drawing, PUT looks acute.
angle PRT = 68 degrees, angle PUT = 96 degrees
Answer:
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

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Step-by-step explanation:
<h3>Given information</h3>


<h3>Question 15. f(g(2))</h3>
<u>Substitute values into the first function</u>



<u>Substitute the values of the first function into the second</u>


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<h3>Question 16. g(f(2.5))</h3>
<u>Substitute values into the first function</u>


<u />
<u>Substitute the values of the first function into the second</u>




<h3>Question 17. g(f(-5))</h3>
<u>Substitute values into the first function</u>


<u>Substitute the values of the first function into the second</u>




<h3>Question 18. f(g(-5))</h3>
<u>Substitute values into the first function</u>



<u>Substitute the values of the first function into the second</u>



Hope this helps!! :)
Please let me know if you have any questions
Length(width + 30)=15,000 square meters, so the equation is l(w+30)=15,000, either 15,000 or 1,500 i cannot tell which number you were meaning to say because of where your comma is placed.