Answer:
B. |-6|<|-7|
Step-by-step explanation:
|-6| = 6
|-7| = 7
and 6 <7 so the answer is B.
Answer:
(0,2)
Step-by-step explanation:
Convert the equation to <em>y=mx+b</em>.
You get y=1/2+2.
Since x is always 0 in your y-intercept and the y value is equal to <em>b, </em>you get (0,2) as your coordinate pair.
Answer:
212 tickets were sold
Step-by-step explanation:
a (adult) + s (student) = 326
8a + 5s = 1972
-5(a + s = 326)
-5a-5s=1630
3a/3 = 342/3
a = 114
114 + s = 326
s = 212
<u>Though there is no specific requirement, we'll compute the perimeter and area of the shown image.</u>
Answer:
<em>The area is 175 square inches</em>
<em>The perimeter is 60 inches</em>
Step-by-step explanation:
<u>Area and Perimeter</u>
We are given a compound shape and it's required to calculate its area and perimeter.
The perimeter is the sum of all its external side lengths. All of them are given thus:
P = 5 + 5 + 10 + 10 + 15 + 15 = 60
The perimeter is 60 inches
Now for the area, we split the figure into two rectangles, one of dimensions 5 in by 5 in (a square) and the other of 10 in by 15 in.
The total area is:
A = 5*5 + 10*15 = 25 + 150
A = 175 square inches
The area is 175 square inches
Answer:
B) 8 cm
Step-by-step explanation:
Hello, I can help you with this
according to the question
The length of a rectangle is 3 cm greater than the width of the rectangle.
convert this into algebraic terms
Step 1
do the eqution
Let
W,width
L,Length
The length of a rectangle(L) is(=) 3 cm greater than the width (W+3) of the rectangle.
note:3 cm greater than the width (W+3) means that you need add 3 to the width to obtain the length
L=W+3 equation(1)
the area of the rectangle is 40 square cm
Let
A,Area
Area= 40 cm
A=40
also,A=L*W
40=L*W equation(2)
Step 2
solve the equations
L=W+3 equation(1)
40=L*W equation(2)
replace the value of L from equaiton (1) into equation (2)
![40=(W+3)*W\\40=W^{2} +3W\\W^{2} +3W-40=0\\W^{2}+3W-40=0\\\\use cuadratic\\\\w=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}\\\\w=\frac{-3+-\sqrt{3^{2}-4*1*-40 } }{2*1}\\w=\frac{-3+-\sqrt{169} }{2}\\](https://tex.z-dn.net/?f=40%3D%28W%2B3%29%2AW%5C%5C40%3DW%5E%7B2%7D%20%2B3W%5C%5CW%5E%7B2%7D%20%2B3W-40%3D0%5C%5CW%5E%7B2%7D%2B3W-40%3D0%5C%5C%5C%5Cuse%20cuadratic%5C%5C%5C%5Cw%3D%5Cfrac%7B-b%2B-%5Csqrt%7Bb%5E%7B2%7D-4ac%20%7D%20%7D%7B2a%7D%5C%5C%5C%5Cw%3D%5Cfrac%7B-3%2B-%5Csqrt%7B3%5E%7B2%7D-4%2A1%2A-40%20%7D%20%7D%7B2%2A1%7D%5C%5Cw%3D%5Cfrac%7B-3%2B-%5Csqrt%7B169%7D%20%7D%7B2%7D%5C%5C)
we are looking for a distance, so we need the positive valur only.
![w=\frac{-3+-\sqrt{169} }{2}\\\\w=\frac{-3+13}{2}\\ w=5\\](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B-3%2B-%5Csqrt%7B169%7D%20%7D%7B2%7D%5C%5C%5C%5Cw%3D%5Cfrac%7B-3%2B13%7D%7B2%7D%5C%5C%20w%3D5%5C%5C)
Step 3
Now, replace the value of W into equation (1) to obtain the length
L=W+3 equation(1)
L=5+3
L=8
so, the length is 8 cm, B) 8 cm
Have a nice day.