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amm1812
3 years ago
7

Helppp pls how do u do this

Mathematics
2 answers:
Dvinal [7]3 years ago
4 0

Answer:

3y / (y+3)

Step-by-step explanation:

3y^2 - 6y / y^2 + y - 6

= 3y(y-2) / (y+3)(y-2)

=3y / (y+3)

Goryan [66]3 years ago
3 0

Answer:

3y / (y+3)

Step-by-step explanation:

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How many ways can 54,625 be written in expanded form
forsale [732]
In the number 54, 625 from left to right:

5 represents 5,
2 represents 20
6 represents 600
4 represents 4000
5 represents 50,000


so 
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54,625=50,000+4,000+600+20+5=5*10,000+4*1000+6*100+2*10+5


another way we can write this number is </span>5.10^4+4.10^3+6.10^2+2.10+5


Answer:
i) 5*10,000+4*1000+6*100+2*10+5
ii) 5.10^4+4.10^3+6.10^2+2.10+5

2 ways, which are essentially the same thing.
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4 years ago
How do we find what x is in this problem
Alexxx [7]
Set The Numbers On The Side Equal To The Equation. Use Inverse Operation And Divide Since The X Is Used In Multiplication.
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3 years ago
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PLEASE HELP FAST! What is the area of a circle with a diameter of 10 cm?
UNO [17]

Answer:

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Step-by-step explanation:

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3 years ago
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Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
3 years ago
Write the equation for a parabola with a focus at (2, 2) and a directrix at x = 8.
Bond [772]

Let  P(x,y) be a point on the parabola.  The definition of a parabola is the squared distance from P to focus F(2,2) equals the squared distance to the directrix x=8.

squared distance from P(x,y) to focus F(2,2)

(x - 2)² + (y - 2)²

squared distance from P(x,y) to the directrix x=8.

(x-8)²

Those are equal in a parabola,

(x - 2)² + (y - 2)² = (x-8)²

x² - 4x + 4 + y² - 4y + 4 = x² - 16x + 64

y² - 4y - 46 = -12x

That's a sideways parabola,

x = -(y² - 4y - 46)/12

8 0
3 years ago
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