1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tekilochka [14]
3 years ago
15

Help plz I really don't get it

Mathematics
2 answers:
bija089 [108]3 years ago
5 0
3 or any number higher
lesantik [10]3 years ago
3 0
The answer is 3 or anything greater than 3.
You might be interested in
4/7 - -3/5 step by step pls explain​
lidiya [134]

Answer:

41/35

Step-by-step explanation:

Simplify the following:

4/7 + 3/5

Put 4/7 + 3/5 over the common denominator 35. 4/7 + 3/5 = (5×4)/35 + (7×3)/35:

(5×4)/35 + (7×3)/35

5×4 = 20:

20/35 + (7×3)/35

7×3 = 21:

20/35 + 21/35

20/35 + 21/35 = (20 + 21)/35:

(20 + 21)/35

| 2 | 1

+ | 2 | 0

| 4 | 1:

Answer: 41/35

5 0
4 years ago
If the probability of surviving a head on car accident at 55 mph is 0.097, then what is the probability of not surviving
BabaBlast [244]

The probability of not surviving a head-on car accident is: 0.903

Step-by-step explanation:

The probabilities of occurrence and non-occurrence of an event add up to one.

If p is the probability that an even will happen and q is the probability that it will not happen

Then

p+q=1

Here,

Probability of surviving = p = 0.097

Probability of not surviving = q = ?

0.097 + q = 1\\q = 1 - 0.097\\q = 0.903

The probability of not surviving a head-on car accident is: 0.903

Keywords: Probability, Inverse

Learn more about probability at:

  • brainly.com/question/4460262
  • brainly.com/question/4464845

#LearnwithBrainly

5 0
3 years ago
Evaluate ∫ xe2x dx. 1 2 3x A./xe +C 6 B.1/xe2x-1/ xe2x+C 22 C.1/xe2x-1/ e2x+C 24 1 2 1 4x D./x-/e +C 28
Dafna1 [17]
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C

Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
     u = x
     dv/dx = e^(2x)

By differentiating u, we get
     du/dx= 1
By integrating dv/dx= e^(2x), we have
     v =∫e^(2x) dx = (1/2)e^(2x)

Then we substitute these values to the integration by parts formula:
     ∫ u(dv/dx) dx = uv −∫ v(du/dx) dx 
     ∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
                          = (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
                          = (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.

Therefore, 
     ∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
7 0
4 years ago
What phrases describes the expression of 16-y​
Jlenok [28]

<em>What phrases describes the expression of 16-y​</em>

<em>Answer: -9</em>

<em></em>

<em>Hope this helps~ </em>

6 0
3 years ago
F( y ) = y + y 2 - 3
ExtremeBDS [4]
F(y) = y + y^2 - 3

f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1

f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9

f(0) = 0 + 0^2 - 3
f(0) = -3

f(2) = 2 + 2^2 - 3
f(2) = 2 + 4 - 3
f(2) = 3

f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17



7 0
4 years ago
Other questions:
  • A survey determined that 5/19 of the seventh grade students at Mills Middle School preferred round chocolate candies to hard can
    14·1 answer
  • I do all things in zero sums in my head is that possible to be a zero?
    7·2 answers
  • Jennifer has 4/5 as many oictures on her camera as luisa does. Jennifer has 28 pictures on her camera. How many pictures do Jenn
    11·1 answer
  • Geometry help for an idiot lol pls help
    6·2 answers
  • Y = -3x + 5? *<br> What’s the slope of the equation y =-3x+5
    11·1 answer
  • Suppose you have $245. If you decide to spend it all on ice cream, you can buy 70 pints. If the price of a glass of lemonade is
    10·1 answer
  • Part b c and d please help
    8·1 answer
  • PLEASE Help mE wiTh the two QUESTIONS
    13·1 answer
  • Please please I beg you help me.
    11·1 answer
  • Helppppppppppp!!!!!!!!!!!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!