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____ [38]
3 years ago
14

If 4.40 g of glucose are burned in a bomb calorimeter, the temperature of the 800 g of water in the calorimeter increases from 1

5.0∘C to 18.7∘C. If the heat capacity of the calorimeter is 550J∘C, what is the value of q for the combustion of the glucose sample?
Chemistry
1 answer:
bixtya [17]3 years ago
3 0

Answer:

-14.4kJ

Explanation:

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Which planet is sometimes called Uranus’s twin? Saturn Pluto Jupiter Neptune
sattari [20]

Neptune.

Because the size, mass, composition and rotation of Neptune and Uranus are very similar they're sometimes refered to as planetary twins.

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3 years ago
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The mass of an object Is 45 kilograms. It’s weight on earth is—— newtons, and it’s weight on the moon is ——newtons. Gravitationa
Lina20 [59]

Answer:

The weight of the object on earth =441N

Weight of the object on moon = 72N

Explanation:

Weight of a body is the product of its mass and acceleration due to gravity. Acceleration due to gravity varies between planetary bodies. The acceleration due to gravity on earth is 9.8 m/s² while on moon is 1.6m/s² and it goes different for others too.

Weight = Mass * acceleration due to gravity

Weight(e) = weight on earth

Weight (m) = weight on moon

Weight(e) = 45 * 9.8 = 441N

Weight (m) = 45 * 1.6 = 72N

Weight of a body is measured in a unit called Newton(N)

8 0
4 years ago
Freeze-drying is a process used to preserve food. If strawberries are to be freeze-dried, then they would be frozen to -80.00 °C
katrin2010 [14]

Answer:

1. 389 kJ; 2. 7.5 µg; 3. 6.25 days

Explanation:

1. Energy required

The water is converted directly from a solid to a gas (sublimation).

They don't give us the enthalpy of sublimation, but

\Delta_{\text{sub}}H = \Delta_{\text{fus}}H + \Delta_{\text{vap}}H = 6.01 + 40.68 = 46.69 \text{ kJ}\cdot\text{mol}^{-1}

The equation for the process is then

Mᵣ:                         18.02

         46.69 kJ + H₂O(s) ⟶ H₂O(g)

m/g:                       150

(a) Moles of water

\text{Moles} = \text{150 g} \times \dfrac{\text{1 mol}}{\text{18.02 g}} = \text{8.324 mol}

(b) Heat removed

46.69 kJ will remove 1 mol of ice.

\text{Heat removed} = \text{8.234 mol} \times \dfrac{\text{46.69 kJ}}{\text{1 mol}} = \textbf{389 kJ}\\\text{It takes $\large \boxed{\textbf{389 kJ}}$ to remove 150 g of ice}

2. Mass of water vapour in the freezer

For this calculation, we can use the Ideal Gas Law — pV = nRT

(a) Moles of water

Data:

p = 1.00 \times 10^{-3}\text{ torr } \times \dfrac{\text{1 atm}}{\text{760 torr}} = 1.316 \times 10^{-6}\text{ atm}

V = 5 L

T = (-80 + 273.15) K = 193.15 K

Calculation:

\begin{array}{rcl}pV & = & nRT\\1.316 \times 10^{-6}\text{ atm} \times \text{5 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{193.15 K }\\6.6 \times 10^{-6} & = & 15.85n\text{ mol}^{-1} \\n & = & \dfrac{6.6 \times 10^{-6}}{15.85\text{ mol}^{-1}}\\\\& = & 4.2 \times 10^{-7} \text{ mol}\\\end{array}

(b) Mass of water

\text{Mass} = 4.2 \times 10^{-7} \text{ mol} \times \dfrac{\text{18.02 g}}{\text{1 mol}} = 7.5 \times 10^{-6}\text{ g} = 7.5 \, \mu \text{g}\\\\\text{At any given time, there are $\large \boxed{\textbf{7.5 $\mu$g}}$ of water vapour in the freezer.}

3. Time for removal

You must remove 150 mL of water.

It takes 1 h to remove 1 mL of water.

\text{Time} = \text{150 mL} \times \dfrac{\text{1 h}}{\text{1 mL}} = \text{150 h} = \text{6.25 days}

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riadik2000 [5.3K]

Answer:

potassium and sodium

Explanation:

when they react with cold water they produce a metal hydroxide and hydrogen gas

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