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Aleksandr [31]
3 years ago
11

Metal ions are typically [a.larger than b.smaller than c.equal in size to] their corresponding neutral atoms. Nonmetal ions are

typically [a.larger than b.smaller than c.equal in size to] than their corresponding neutral atoms.

Chemistry
2 answers:
Mariana [72]3 years ago
5 0

Metal ions are typically b. smaller than their corresponding neutral atoms.

When we form a metal ion, we are <em>removing the outermost (valence) electrons</em> and exposing the smaller inner core.

Non-metal ions are typically a. larger than their corresponding neutral atoms.

The <em>added electrons repel each other</em>, so the electron cloud becomes larger.

Olenka [21]3 years ago
4 0

An atom consists of a central nucleus with positively charged protons and neutral neutrons. Negatively charged electrons revolve around the nucleus along electronic shells. A metal atom has the tendency to lose electrons from the outermost electronic shell to form a positive ion known as cation. In a cation, the number of electrons is less than the protons in the nucleus. As a result, electrons are attracted towards the nucleus by a strong force of attraction. This makes metal ions smaller than their corresponding neutral atoms.

(Ans) (b) smaller than

A nonmetal atom usually gains electrons to form a negative ion or anion. In an anion the number of electrons is more. As a result, electrons start to repel with each other and the electrons spread out. This increases the size of anions. For this reason, nonmetal ions are typically larger than their corresponding neutral atoms.

(Ans) (a) larger than

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3 years ago
A 12 gram piece of metal is heated to 300 °C from 100 °C with 1120 Joules of energy. What is the specific heat of the metal?
Sergeeva-Olga [200]

Answer:

The specific heat for the metal is 0.466 J/g°C.

Explanation:

Given,

Q = 1120 Joules

mass = 12 grams

T₁ = 100°C

T₂ = 300°C

The specific heat for the metal can be calculated by using the formula

Q = (mass) (ΔT) (Cp)

ΔT = T₂ - T₁ = 300°C  - 100°C   = 200°C

Substituting values,

1120 = (12)(200)(Cp)

Cp = 0.466 J/g°C.

Therefore, specific heat of the metal is 0.466 J/g°C.

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8 0
3 years ago
What is the ratio of lactic acid (Ka = 1.37x^10-4) to lactate in a solution with pH =4.29
hram777 [196]

Henderson–Hasselbalch equation is given as,

                                         pH  =  pKa  +  log [A⁻] / [HA]   -------- (1)

Solution:

Convert Ka into pKa,

                                         pKa  =  -log Ka

                                         pKa  =  -log 1.37 × 10⁻⁴

                                         pKa  =  3.863

Putting value of pKa and pH in eq.1,

                                         4.29  =  3.863 + log [lactate] / [lactic acid]

Or,

                   log [lactate] / [lactic acid]  =  4.29 - 3.863

                   log [lactate] / [lactic acid]  =  0.427

Taking Anti log,

                             [lactate] / [lactic acid]  =  2.673

Result:

           2.673 M  lactate salt when mixed with 1 M Lactic acid produces a buffer of pH = 4.29.

6 0
3 years ago
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