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Aleksandr [31]
3 years ago
11

Metal ions are typically [a.larger than b.smaller than c.equal in size to] their corresponding neutral atoms. Nonmetal ions are

typically [a.larger than b.smaller than c.equal in size to] than their corresponding neutral atoms.

Chemistry
2 answers:
Mariana [72]3 years ago
5 0

Metal ions are typically b. smaller than their corresponding neutral atoms.

When we form a metal ion, we are <em>removing the outermost (valence) electrons</em> and exposing the smaller inner core.

Non-metal ions are typically a. larger than their corresponding neutral atoms.

The <em>added electrons repel each other</em>, so the electron cloud becomes larger.

Olenka [21]3 years ago
4 0

An atom consists of a central nucleus with positively charged protons and neutral neutrons. Negatively charged electrons revolve around the nucleus along electronic shells. A metal atom has the tendency to lose electrons from the outermost electronic shell to form a positive ion known as cation. In a cation, the number of electrons is less than the protons in the nucleus. As a result, electrons are attracted towards the nucleus by a strong force of attraction. This makes metal ions smaller than their corresponding neutral atoms.

(Ans) (b) smaller than

A nonmetal atom usually gains electrons to form a negative ion or anion. In an anion the number of electrons is more. As a result, electrons start to repel with each other and the electrons spread out. This increases the size of anions. For this reason, nonmetal ions are typically larger than their corresponding neutral atoms.

(Ans) (a) larger than

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3 years ago
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Which ONE of the following compounds is least soluble in water?
Zepler [3.9K]

Answer:

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Explanation:

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4 0
2 years ago
Find the grams of iron in 79.2 g of Fe2O3.
Setler79 [48]
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112 + 48 = 160

Moles = mass/RFM
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Then you rearrange the formula
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(To find mass of Iron have to use RFM of total iron in the substance example Fe2 ^^)


3 0
2 years ago
A chemical supply company sells a concentrated solution of aqueous h2so4 (molar mass 98 g mol−1 ) that is 50. percent h2so4 by m
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Answer is: <span>the molarity of the sulfuric acid is 7.14 M.
</span>ω(H₂SO₄) = 50% ÷ 100% = 0.5.<span>
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V(H₂SO₄) = 100 mL ÷ 1000 mL/L = 0.1 L..
mr(H₂SO₄) = d(H₂SO₄) · V(H₂SO₄).
mr(H₂SO₄) = 1.4 g/mL · 100 mL.
mr(H₂SO₄) = 140 g.
m(H₂SO₄) = ω(H₂SO₄) · mr(H₂SO₄).
m(H₂SO₄) = 0.5 · 140 g.
m(H₂SO₄) = 70 g.
n(H₂SO₄) = m(H₂SO₄) ÷ M(H₂SO₄).
n(H₂SO₄) = 70 g ÷ 98 g/mol.
n(H₂SO₄) = 0.714 mol.
c(H₂SO₄) = n(H₂SO₄) ÷ V(H₂SO₄).
c(H₂SO₄) = 0.714 mol ÷ 0.1 L.
C(H₂SO₄) = 7.14 M.
8 0
2 years ago
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