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Alexeev081 [22]
3 years ago
10

Which planet is sometimes called Uranus’s twin? Saturn Pluto Jupiter Neptune

Chemistry
2 answers:
sattari [20]3 years ago
7 0

Neptune.

Because the size, mass, composition and rotation of Neptune and Uranus are very similar they're sometimes refered to as planetary twins.

kiruha [24]3 years ago
4 0

Answer: Neptune

Explanation: There are a bunch of physical, chemistry and geographic properties that ubicates to neptune as twin with uranus, for example The size, mass, composition and rotation of Uranus and Neptune are extremely similar.

Inclusive you can find investigation of the NASA that proof the similarity between this beautiful planets.

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Which of the following statements about the carbon cycle is NOT true?
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Answer:

Plants consume carbon through transpiration

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In transpiration, plants lose water vapor through the stomata in their leaves. No carbon is involved in transpiration, which has an outbound direction. Nothing can be consumed through the stomata when vapor is going out of the plant. It´s like trying to get in through the exit.

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How many gallon are there in 85.00 L?
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22.46

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How would a 2+ ion form from an atom?
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A 110.0-mL sample of a solution that is 3.0×10−3 M in AgNO3 is mixed with a 230.0- mL sample of a solution that is 0.10 M in NaC
almond37 [142]

Answer:

[Ag⁺] = 0.0666M

Explanation:

For the addition of Ag⁺ and CN⁻, the (Ag(CN)₂⁻ is produced, thus:

Ag⁺ + 2CN⁻  ⇄  Ag(CN)₂⁻

Kf = 1x10²¹ = [Ag(CN)₂⁻] / [CN⁻]² [Ag⁺]

As initial concentrations of Ag⁺ and CN⁻ are:

[Ag⁺] = 0.110L × (3.0x10⁻³mol / L) = 3.3x10⁻⁴mol / (0.110L + 0.230L) = 9.7x10⁻⁴M

[CN⁻] = 0.230L × (0.1mol / L) = 0.023mol / (0.110L + 0.230L) = 0.0676M

The equilibrium concentrations of each compound are:

[CN⁻] = 9.7x10⁻⁴M - x

[Ag⁺] = 0.0676M - x

[Ag(CN)₂⁻] = x

<em>Where x is reaction coordinate</em>

Replacing in Kf formula:

1x10²¹ = [x] / [9.7x10⁻⁴M - x]² [0.0676M - x]

1x10²¹ = [x] / 6.36048×10⁻⁸ - 0.000132085 x + 0.06954 x² - x³

-1x10²¹x³ + 6.954x10¹⁹x² - 1.32085x10¹⁷ x + 6.36x10¹³ = x

-1x10²¹x³ + 6.954x10¹⁹x² - 1.32085x10¹⁷ x + 6.36x10¹³ = 0

Solving for x:

X = 9.614x10⁻⁴M

Thus, equilibrium concentration of Ag⁺ is:

[Ag⁺] = 0.0676M - 9.614x10⁻⁴M = <em>0.0666M</em>

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3 years ago
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