Equation of the circle is
(x-h)² + (y-k)² = r²,
where (h, k) are coordinates of the center of the circle.
(h,k)= (0,-2)
radius r= 6
(x-0)² +(y-(-2))²=6²
x² + (y+2)² = 36
The answer is B hope it helps
sin(x+y)=sin(x)cos(y)-cos(x)sin(y)
also, remember pythagorean rule, 
given that sin(Θ)=4/5 and cos(x)=-5/13
find sin(x) and cos(Θ)
sin(x)
cos(x)=-5/13
using pythagorean identity
(sin(x))^2+(-5/13)^2=1
sin(x)=+/- 12/13
in the 2nd quadrant, sin is positve so sin(x)=12/13
cos(Θ)
sin(Θ)=4/5
using pythagrean identity
(4/5)^2+(cos(Θ))^2=1
cos(Θ)=+/-3/5
in 1st quadrant, cos is positive
cos(Θ)=3/5
so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)
sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)
sin(Θ+x)=16/65
answer is 1st option
Answer:
options 3 and 6
Step-by-step explanation:
the exponent x+2 means that the graph moves to the left 2 units and the value of K, which is -4, means that the graph will then move down 4 units from the parent function f(x)