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Answer:
2.5 it is the absolute value
Step-by-step explanation:
brainliest plz
Answer:
If p is the smallest of n consecutive integers of the same sign than we have p , p+1 , p+2 , … , p+(n−1) ,
So the sum is
∑k=0n−1(p+k)=∑k=0n−1p+∑k=0n−1k=np+n2−n2
Here n=4
So we have 4p+6
And checking
p+(p+1)+(p+2)+(p+3)=4p+6
Note if p=−v
Than you have the same thing as if p=v−n+1 just negative for example 3 consecutive integers the smallest is −5 so the sum is −5+(−4)+(−3)=3×−5+32−32=−15+3=−12
On the other hand:
−(3+4+5)=−(3×3+32−32)=−(9+3)=−12
If p=−v the sum of next v+1 integers is −(∑k=0vk)=−(v2+v2)
Than needs an other v integers to bring it up to 0 again. From there it is
∑k=0hk=h2+h2
Where h=n−(2v+1) .
So recap if p is the smallest of n consecutive integers their sum is
p+(p+1)+(p+2)+…+(p+(n−1))=⎧⎩⎨⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪np+n2+n2−(n|p|+n2+n2)((n−|p|)2+(n−|p|)2)−(|p|p+|p|2+|p|2)((n−|p|)2+(n−|p|)2)n≥0p<0∧n<|p|+1p<0∧|p|<n<2|p|+1p<0∧n>2|p|+1
Step-by-step explanation:
The factored form of the related polynomial is (x - 1)(x - 9)
<h3>How to determine the
factored form of the related polynomial?</h3>
In this question, the given parameter is the attached graph
From the graph, we can see that the curve crosses the x-axis at two different points
These points are the zeros of the polynomial function.
From the graph, the points are
x = 1 and x = 9
Set these points to 0
x - 1 = 0 and x - 9 = 0
Multiply the above equations
(x - 1)(x - 9) = 0
Remove the equation
(x - 1)(x - 9)
Hence, the factored form of the related polynomial is (x - 1)(x - 9)
Read more about polynomial at:
brainly.com/question/4142886
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Answer: 160
Step-by-step explanation:
160 is the answer trust me
