Question

Help me please Surds

Answer 1

Answer:

12$\sqrt{6}$ + 8$\sqrt{15}$ + 12 + 4$\sqrt{10}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

(4$\sqrt{3}$ + 2$\sqrt{2}$ )(3$\sqrt{2}$ + 2$\sqrt{5}$ )

Each term in the second factor is multiplied by each term in the first factor, that is

4$\sqrt{3}$ (3$\sqrt{2}$ + 2$\sqrt{5}$ ) + 2$\sqrt{2}$ (3$\sqrt{2}$ + 2$\sqrt{5}$ ) ← distribute both parenthesis

= 12$\sqrt{6}$ + 8$\sqrt{15}$ + 12 + 4$\sqrt{10}$