3 years ago

What is the equation of a line passing through (-3,7) and having a slip of -1/5

Mathematics

1 answer:

MrRa [10]3 years ago

3 0

Answer:

$\large\boxed{D.\ y=-\dfrac{1}{5}x+\dfrac{32}{5}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the slope m = -1/5. Substitute:

$y=-\dfrac{1}{5}x+b$

Put the coordinates of the given point (-3, 7) to the equation:

$7=-\dfrac{1}{5}(-3)+b$

$7=\dfrac{3}{5}+b$ subtract 3/5 from both sides

$6\dfrac{2}{5}=b\to b=\dfrac{6\cdot5+2}{5}=\dfrac{32}{5}$

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