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Margarita [4]
3 years ago
12

What is the equation of a line passing through (-3,7) and having a slip of -1/5

Mathematics
1 answer:
MrRa [10]3 years ago
3 0

Answer:

\large\boxed{D.\ y=-\dfrac{1}{5}x+\dfrac{32}{5}}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

We have the slope m = -1/5. Substitute:

y=-\dfrac{1}{5}x+b

Put the coordinates of the given point (-3, 7) to the equation:

7=-\dfrac{1}{5}(-3)+b

7=\dfrac{3}{5}+b            <em>subtract 3/5 from both sides</em>

6\dfrac{2}{5}=b\to b=\dfrac{6\cdot5+2}{5}=\dfrac{32}{5}

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