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3 years ago

What is the equation of a line passing through (-3,7) and having a slip of -1/5

Mathematics

1 answer:

MrRa [10]3 years ago

3 0

Answer:

$\large\boxed{D.\ y=-\dfrac{1}{5}x+\dfrac{32}{5}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the slope m = -1/5. Substitute:

$y=-\dfrac{1}{5}x+b$

Put the coordinates of the given point (-3, 7) to the equation:

$7=-\dfrac{1}{5}(-3)+b$

$7=\dfrac{3}{5}+b$ <em>subtract 3/5 from both sides</em>

$6\dfrac{2}{5}=b\to b=\dfrac{6\cdot5+2}{5}=\dfrac{32}{5}$

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What is -2 = 5 / (2x+3)

LUCKY_DIMON [66]

Answer:

x = -11/4

Step-by-step explanation:

Given that:

-2 = 5 / (2x+3)

Multiplying both sides by (2x + 3)

-2(2x + 3) = 5

"-" sign will alter the inner signs

-4x -6 = 5

Adding 6 on both sides:

-4x -6 +6 = 5 + 6

-4x = 11

Dividing both sides by -4

-4x/-4 = 11/-4

x = -11/4

i hope it will help you!

3 0

3 years ago

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Anni [7]

Answer:

The answer is 4

Step-by-step explanation:

5 0

3 years ago

The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic

pishuonlain [190]

The five-number summary and the interquartile range for the data set are given as follows:

Minimum: 24.

Lower quartile: 29.

Median: 43.

Upper quartile: 50.

Maximum: 56.

Interquartile range: 50 - 29 = 21.

<h3>What are the median and the quartiles of a data-set?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.

The first quartile is the median of the first half of the data-set.

The third quartile is the median of the second half of the data-set.

The interquartile range is the difference between the third quartile and the first quartile.

In this problem, we have that:

The minimum value is the smallest value, of 24.

The maximum value is the smallest value, of 56.

Since the data-set has odd cardinality, the median is the middle element, that is, the 7th element, as (13 + 1)/2 = 7, hence the median is of 43.

The first quartile is the median of the six elements of the first half, that is, the mean of the third and fourth elements, mean of 29 and 29, hence 29.

The third quartile is the median of the six elements of the second half, that is, the mean of the third and fourth elements of the second half, mean of 49 and 51, hence 50.

The interquartile range is of 50 - 29 = 21.

More can be learned about five number summaries at brainly.com/question/17110151

#SPJ1

3 0

2 years ago

Barbara gets 6 pizza to divide equally among 4 people. How much of a pizza can each person ?

kozerog [31]

Your key word is divide. You'll want to divide your 6 pizzas by your four friends, than most likely convert it to a fraction (unless your teacher accepts decimals.), message if you need more help.

3 0

3 years ago

Read 2 more answers

The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses.

Luden [163]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

If we had increased the confidence level, the margin of error also would have increased.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96. Increasing the confidence level, z also increases, hence the margin of error also would have increased.

The sample size and the estimate are given as follows:

$n = 450, \pi = 0.47$ .

The lower and the upper bound of the interval are given, respectively, by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 - 1.96\sqrt{\frac{0.47(0.53)}{450}} = 0.4239$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.47 + 1.96\sqrt{\frac{0.47(0.53)}{450}} = 0.5161$

The 95% confidence interval for the proportion of college students who work to pay for tuition and living expenses is: (0.4239, 0.5161).

More can be learned about the z-distribution at brainly.com/question/25890103

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5 0

1 year ago