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Paul [167]
3 years ago
15

Please lmk if it is true or false

Mathematics
1 answer:
Nostrana [21]3 years ago
5 0

▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

Yes, the above statement is True.

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Will give brainliest!
miv72 [106K]

Answer:

it means that the roots of the quadratic equation is real and distinct and that means that 40 is a positive value

6 0
3 years ago
3.) Simplify the expression by combining like
Evgesh-ka [11]

45s^2-19-s^2+16\\=45s^2-s^2-19+16\\=s^2(45-1)-19+16\\=44s^2+(-19+16)\\=44s^2-3

Hope that helps and hope you get better!

3 0
3 years ago
Can someone help please help sorry I know it’s easy but ......
NARA [144]

Answer:

standard

Step-by-step explanation:

4 0
3 years ago
How do you find the equation of a triangles altitude using point slope formula?
forsale [732]
<span><span><span>1. An altitude of a triangle is a line segment from a vertex perpendicular to the opposite side. Find the equations of the altitudes of the triangle with vertices (4, 5),(-4, 1) and (2, -5). Do this by solving a system of two of two of the altitude equations and showing that the intersection point also belongs to the third line. </span>
(Scroll Down for Answer!)</span><span>Answer by </span>jim_thompson5910(34047)   (Show Source):You can put this solution on YOUR website!
<span>If we plot the points and connect them, we get this triangle: 

 

Let point 
A=(xA,yA)
B=(xB,yB)
C=(xC,yC) 



------------------------------- 
Let's find the equation of the segment AB 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through AB is  


------------------------------- 
Let's find the equation of the segment BC 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through BC is  




------------------------------- 
Let's find the equation of the segment CA 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through CA is  




So we have these equations of the lines that make up the triangle 


 



So to find the equation of the line that is perpendicular to  that goes through the point C(2,-5), simply negate and invert the slope  to get 

Now plug the slope and the point (2,-5) into  


 

 Solve for y and simplify 

So the altitude for vertex C is  



Now to find the equation of the line that is perpendicular to  that goes through the point A(4,5), simply negate and invert the slope to get  

Now plug the slope and the point (2,-5) into  


 

 Solve for y and simplify 

So the altitude for vertex A is  




Now to find the equation of the line that is perpendicular to  that goes through the point B(-4,1), simply negate and invert the slope to get  

Now plug the slope and the point (-4,1) into  


 

 Solve for y and simplify 

So the altitude for vertex B is  



------------------------------------------------------------ 
Now let's solve the system 


 

 Plug in  into the first equation 

 Add 2x to both sides and subtract 2 from both sides 

 Divide both sides by 3 to isolate x 


Now plug this into  

 

 



So the orthocenter is (-2/3,1/3) 

So if we plug in  into the third equation , we get 


 


 


 

 

So the orthocenter lies on the third altitude 





</span><span>
</span></span>
3 0
3 years ago
Which statement explains how the lines 2x + y = 4 and y = one halfx + 4 are related?
KatRina [158]

Answer:

They are perpendicular

Step-by-step explanation:

To solve this problem .

we will convert the equations in slope intercept form.

Slope intercept  form of equation is y = mx+c

where m is slope of line and c is y intercept.

________________________________

equation 1 is

2x+y = 4

=> y =4 - 2x or y = -2x + 4

comparing it with y = mx + c

m = -2  , c = 4

_________________________________________

equation 2 is y = one halfx + 4 ( one half is same as 1/2)

so equation is

y = x/2 +4

comparing it with y = mx + c

m = 1/2  , c = 4

_________________________________________

Now lets evaluate options

They are parallel.  wrong option

For lines to be parallel slope should be same.

But here slope are different -2 and 1/2 .

Thus lines are not parallel.

__________________________________________

They are perpendicular.  correct option

For lines to be perpendicular, product of slope should be equal to -1.

-2*1/2 = -1

we can see that product of slope should be equal to -1 .

Thus lines are  perpendicular

______________________________________

They are the same line.  wrong option

For lines to be same both slope and y intercept should  be same.

Y intercept is same but the slopes are different -2 and 1/2  .

Thus lines are not  the same line.

__________________________________________

They are not related.       wrong option

As we have found that the lines are perpendicular .

So this option is intuitively wrong

4 0
3 years ago
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