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3 years ago

Solving quadratic equations using square roots

Mathematics

1 answer:

masya89 [10]3 years ago

8 0

Answer:

i hope you understand this

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The sum of the circumference of two circles is 38π cm and the sum of their areas is 193π cm². Calculate the radii of the circles

sdas [7]

Answer:

The radii of the circles are 12 cm and 7cm.

Step-by-step explanation:

Let the radii of the circles be $r_{1}\ and\ r_{2}$

Given:

Sum of circumference of two circles= 38π cm

Formula for circumference of a circle with radius r = 2πr

$2\pi r_{1}+2\pi r_{2}=38\pi \\r_{1}+r_{2}=19$ ------------1

Sum of areas of two circles= 193π cm²

Area of circle with radius r = πr²

$\pi r_{1}^{2}+\pi r_{2}^{2}=193\pi \\r_{1}^{2}+r_{2}^{2}=193$ -------2

Substituting r2 = 19 - r1 in equation 2 we get:

$r_{1}^{2}+(19-r_{1})^{2}=193\\2r_{1}^{2}-38r_{1}+168=0\\r_{1}^{2}-19r_{1}+84=0\\(r_{1}-12)(r_{1}-7)=0\\r_{1}=12\ or\ 7$

Then r2 = 19 - r1

$r_{2}=12\ or\ 7$

7 0

3 years ago

Eva needs to order some new supplies for the restaurant where she works. The

olasank [31]

Answer:

s≥32

Step-by-step explanation:

Subtract 173 from 749: 576

since each set has 18 forks, divide 576 by 18: 32

since the restaurant needs at LEAST 32 more sets, s has to be greater or equal to 32

3 0

3 years ago

A car on a racetrack drove 98 miles in 60 minutes. How far did it drive in 12 minutes? Round the the nearest tenth when necessar

Alborosie

Answer:

19.6 miles in 12 minutes.

Step-by-step explanation:

first take 60, then divide it by 12.

60÷12=5

then take 98 and divide that by 5

98÷5=19.6

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3 years ago

~Giving brainliest!~ (im really desperate right now and very overwhelmed so im asking ANYONE to help me answer this! thank u.

ryzh [129]

What’s the question?

7 0

3 years ago

Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.

Assoli18 [71]

Answer:

±11.18

Step-by-step explanation:

the function is:

$f(q)=q^2-125$

and to find the roots we need to find which values of $q$ makes the function result in zero:

$q^2-125=0$

solving for $q$ :

$q^2=125\\q=\sqrt{125}$

A square root has two solutions, one positive and one negative, so the solutions are:

$q=$ ± $\sqrt{125}$ ≈ ±11.18

the roots of the quadratic equation are +11.18 and -11.18

3 0

4 years ago

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