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3 years ago

In a mixed school of 732 pupils 132 are girls. What is the fraction of the pupils who are boys

Mathematics

2 answers:

murzikaleks [220]3 years ago

5 0

600/732 because out of 732, 132 pupils are girls.

ad-work [718]3 years ago

5 0

It will be 600 because you can say 732-132=600

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3 years ago

Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)

Xelga [282]

Answer:

$\frac{x^2}{16}-\frac{b^2}{4}=1$

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4$

The foci c is at +/-2√5, using c² = a² + b²:

$c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2$

Substituting the value of a and b to get the equation of the hyperbola:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1$

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3 years ago

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Answer:

5(25 + z)

Step-by-step explanation:

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(25 + z)(5), or 5(25 + z).

This result can be left as is, or rewritten as 125 + 5z.

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3 years ago

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Step-by-step explanation:

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3 years ago

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nikklg [1K]

Answer:

alex has 25 counters

Step-by-step explanation:

8x4=32

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2 years ago

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In a mixed school of 732 pupils 132 are girls. What is the fraction of the pupils who are boys​

In a mixed school of 732 pupils 132 are girls. What is the fraction of the pupils who are boys