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2 years ago

Men's socks. Cost $8.00 for a package of three. How much would two dozen socks cost ?

Mathematics

1 answer:

weeeeeb [17]2 years ago

4 0

1 dozen = 12

12 x 2 = 24

8/3 = x/24
3x=192
x=64

two dozen socks would cost $64

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Need help thanks!!!!!!

kherson [118]

Answer:

Step-by-step explanation:

$-----------------------------$

$Here's$ $how$ $we$ $solve$ $the$ equation

$-1.2\left(3-x\right)$ = $-1.8$

$-1.2\left(3-1.5\right)$ = $-1.8$

$-3.6+1.2\cdot1.5$ = $-1.8$

$1.2\cdot1.5$ = $-1.8$

$-----------------------------$

<em>Hope this helps! <3</em>

5 0

2 years ago

What is the value of x in the solution to this system of equations? 3x = 2y + 14<br> y = -6x + 18

zmey [24]

Use substitution
3x = 2(-6x + 18) + 14
3x = -12x + 36 + 14
3x = -12x + 50
15x = 50, x = 50/15 = 10/3
Solution: x = 10/3

4 0

2 years ago

Anita is making a curtain to surround a table. She bought 3 1/4 yards of fabric. Her total cost was $13. What was the cost per y

Ratling [72]

3.25y=13. Isolate y by dividing both sides of the equation by 3.25. So 3.25y/3.25=13/3.25. Your answer is therefore 13/3.25, or 4

7 0

2 years ago

Read 2 more answers

Write an algebraic expression for the perimeter of a rectangular garden with a width of 3 metres and a length of 2y metres. Simp

anyanavicka [17]

Answer:

P = 2(2y+3)

P = 30

Step-by-step explanation:

P = 2 (L+W) or P = L + L + W + W

P = 2 (2y+3)

P = 4y+6

Plug in 6 for y.

P = 24+6

P = 30

5 0

2 years ago

Consumer products are required by law to contain at least as much as the amount printed on the package. For example, a bag of po

Troyanec [42]

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, $\sigma=0.2$ ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

$P(x\geq 10)=0.99$

Assume the bag weight distribution is bell-shaped

Therefore,

$P(\frac{x-\mu}{\sigma}\geq 10)=0.99$

We know that

$z=\frac{x-\mu}{\sigma}$

Using the value of z

Now,

$\frac{10-\mu}{0.2}=0.99$

$10-\mu=0.99\times 0.2$

$\mu=10-0.99\times 0.2$

$\mu=9.802$

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

5 0

2 years ago