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3 years ago

Solve for x simple geometry

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

Answer:

From the above attachment we can conclude that,

$(2x - 10)° + (4x + 16)° = 180° \\ 2x - 10 + 4x + 16 = 180 \\ 2x + 4x - 10 + 16 = 180 \\ 6x + 6 = 180 \\ 6x = 180 - 6 \\ 6x = 174 \\x = \frac{174}{6} \\ \boxed{x = 29}$

Therefore, the value of x is 29

<u>x = 29</u> is the right answer.

Evgen [1.6K]3 years ago

4 0

Step-by-step explanation:

$2x - 10 + 4x + 16 = 180 \\ \\ 4x - 2x + 16 + 10 = 180 \\ \\ 2x = 180 - 26 \\ \\ 2x = 154 \\ \\ x = \frac{154}{2} \\ \\ x = 77$

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Elina [12.6K]

Answer:25

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3 years ago

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Dmitry [639]

Answer:

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3 years ago

The graph of the function f(x) = -(x+6)(x + 2) is shown

Leokris [45]

Answer:

The function is increasing for all real values of x where

x < –4.

Step-by-step explanation:

we have

$f(x)=-(x+6)(x+2)$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex (h,k) represent a maximum

The roots of the function (or x-intercepts) are x=-6 and x=-2

The x-coordinate of the vertex is the midpoint of the roots

$h=(-2-6)/2=-4$

The y-coordinate of the vertex is

substitute the x-coordinate of the vertex in the quadratic equation

$k=-(-4+6)(-4+2)$

$k=-(2)(-2)$

$k=4$

The vertex is the point (-4,4)

The function is increasing in the interval (-∞,-4)

The function is decreasing in the interval (-4,∞)

6 0

3 years ago

Read 2 more answers

Under social distancing and safe shopping restrictions, Krogers currently is allowing a density of 1 customer per 120 square

nlexa [21]

Answer:

1166.

Step-by-step explanation:

The total area of the shopping space is

$350*400=140000$

If 1 customer is allowed per every 120 square foot, then we can work out the maximum capacity by dividing the total.

$\frac{140000}{120}=1166.67$

As we can't have .67 of a customer, we need to round this value down to 1166 customers.

7 0

3 years ago

The points at x equals=_______ and xequals=_______ are the inflection points on the normal curve

uysha [10]

We know that the probability density function of a variable that is normally distributed is f(x) = 1/(σ√2π) * exp[1/2 (x – µ). Its inflection point is the point where f"(x) = 0.
Taking the first derivative, we get f'(x) = –(x–µ)/(σ³/√2π) exp[–(x–µ)²/(2σ²)] = –(x–µ) f(x)/σ².
The second derivative would be f"(x) = [ –(x–µ) f(x)/σ]' = –f(x)/σ² – (x–µ) f'(x)/σ² = –f(x)/σ² + (x-µ)² f(x)/σ⁴.
Setting this expression equal to zero, we get
–f(x)/σ² + (x-µ)² f(x)/σ⁴ = 0
Multiply both sides by σ⁴/f(x):
–σ² + (x-µ)² = 0
(x-µ)² = σ²
x-µ= + – σ
x = µ +– σ
So the answers are x = µ – σ and x = µ + σ.

8 0

3 years ago