<span>
as cosec theeta is inverse of sin theeta:
so
csc0=1/sin0
and sin0=0 when 0={0.pi,and 2pi}
when 0=0.pi,and 2pi</span>
<span>First, we write an equation to represent that the fencing lengths add up to 568 feet. we call the side of the fence that has three segments of its length x and the side with only two segments y. We write 3x + 2y = 568. We also know that the area of the rectangle is equal to xy, so area = xy. We put y in terms of x using our first equation and find that y = (568 - 3x)/2. We plug this into our area equation and find that area = (568x - 3x^2)/2. To find the maximum we set the derivative equal to 0 and end up with 0 = 284 - 3x. We solve for x and get 94 and 2/3. We then put that into our first equation to find y = 142. So the dimensions that maximize the area are 94 2/3 x 142.</span>
Answer:
36UNITS
Step-by-step explanation:
If point V lies between U and W, then UV+VW = UW
given parameters
UV = 2x-4
VW = 4x+10
UW = 9x-9
Substituting the given functions in the formula first, we will have;
2x-4+4x+10 = 9x-9
6x+6 = 9x-9
Collect like terms
6x-9x = -9-6
-3x = -15
x = -15/-3
x = 5
Substitute x = 5 into UW.
Since UW = 9x-9
UW = 9(5)-9
UW = 45-9
UW = 36
To get the percentage of area we shall proceed as follows:
linear scale factor =length of herb/ length of garden
=4/10
but
area scale factor=(linear scale factor)^2
area scale factor=(2/5)^2=4/25
thus the percentage area proportion will be:
4/25*100
=16%
Answer:
slope is 2. y-intercept is (0,5)
Step-by-step explanation:
The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. y = mx + b. Find the values of m and b using the form y = mx + b.
