We have that
<span>log10 E = 4.4 + 1.5<span>M
</span></span>E=<span>the released energy in Joules (J)
M= </span><span>earthquake measures---------- > 3.6
</span>log10 E = 4.4 + 1.5*3.6
log10 E = 9.8----------> E=10^(9.8)= 6.309573444 x10^9 J
<span>
the answer is </span>6.309573444 x10^9 J<span>
</span>
Answer:
A ≈ 35.3 units²
Step-by-step explanation:
Calculate the radius CB using Pythagoras' identity in the right triangle.
CB² + AB² = AC²
CB² + 6² = 9²
CB² + 36 = 81 ( subtract 36 from both sides )
CB² = 45 = r²
Then area of quarter circle is
A =
× πr² =
× π × 45 ≈ 35.3
2.9 × 1.7 = 4.93
After 1.7 seconds, the puck's speed would be 4.93 meters per second.
I think B is the closest answer