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lapo4ka [179]
3 years ago
11

Alexandra needed to get her computer fixed. She took it to the repair store. The technician at the store worked on the computer

for 5.25 hours and charged her $58 for parts. The total was $661.75. Write and solve an equation which can be used to determine xx, the cost of the labor per hour.
Mathematics
1 answer:
Kamila [148]3 years ago
4 0

Answer:

im not too sure.

Step-by-step explanation:

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What is the measure of angle 1?
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Answer:

92°

Step-by-step explanation:

because 1 is parallel to the 92°

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What is 708 divided by 67 with a remainder?
Kamila [148]

Answer:

10 Remainder 38  i think

Step-by-step explanation:

6 0
3 years ago
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The area of the rectangle shown is given by the function A(x) = 2x2 - 5x. If the width of the rectangle is 13, what is the area
Rudiy27
If the width of the reactangle is x=13, the area of the rectangle is:
A(13)=2*(13)^2-5*(13)
A(13)=2*(169)-65
A(13)=338-65
A(13)=273

The area of the rectangle is 273 square units 
5 0
3 years ago
Estimate the unit rate. $2.35
vovangra [49]
If $2.35 is the unit rate, the estimated one is $2.40 if it is to the nearest tenth, $1.00 to the nearest ones. I may be wrong.
4 0
3 years ago
A newspaper published an article about a study in which researchers subjected laboratory gloves to stress. Among 225 vinyl? glov
romanna [79]

Answer:

a)

H₀: ρ₁ ≤ ρ₂

H₁: ρ₁ > ρ₂

b)

Z= \frac{('p_{1} - 'p_{2}) - (p_{1} - p_{2})}{\sqrt{'p(1-'p)[\frac{1}{n_1} + \frac{1}{n_2} ]} } ≈ N(0;1)

c)

p-value < .00001

d)

Reject the null hypothesis.

The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.

Step-by-step explanation:

Hello!

The objective is to test if the population proportion of vinyl gloves that leak viruses (population 1) is greater then the population proportion of latex gloves that leak viruses (population 2).

Sample 1 (Vinyl)

n₁= 225

Sample proportion 'ρ₁= 0.60

Sample 2 (Latex)

n₂= 225

Sample proportion 'ρ₂= 0.09

Pooled proportion: 'ρ= (x₁+x₂)/(n₁+n₂)= ( 'ρ₁ + 'ρ₂)/2= (0.60 + 0.09)/2= 0.345 ≅0.35

The hypothesis is:

H₀: ρ₁ ≤ ρ₂

H₁: ρ₁ > ρ₂

α: 0.05

The statistic to use is a pooled Z

Z= \frac{('p_{1} - 'p_{2}) - (p_{1} - p_{2})}{\sqrt{'p(1-'p)[\frac{1}{n_1} + \frac{1}{n_2} ]} } ≈ N(0;1)

The critical region is one-tailed to the right (positive), the critical value is:

Z_{1-\alpha } = Z_{0.95} = 1.64

If Z ≥ 1.64, you will reject the null hypothesis.

If Z < 1.64, you will not reject the null hypothesis.

Z= \frac{(0.6 - 0.09) - (0}{\sqrt{0.35(1-0.35)[\frac{1}{225} + \frac{1}{225} ]} } = 11.34

Since the calculated Z- value is greater than the critical value, the decision is to reject the null hypothesis. The population proportion vinyl gloves that leak viruses is greater than the population proportion of latex gloves that leak viruses.

P-value approach:

p-value < .00001

If you compare with the level of signification, you reach the same decision.

I hope it helps!

8 0
4 years ago
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