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Akimi4 [234]
3 years ago
10

What is the area of the base?

Mathematics
1 answer:
MAXImum [283]3 years ago
7 0

Answer:

24 in²

Step-by-step explanation:

Hello there!

the figure shown is a triangular prism

The base is the triangle

So we need to find the area of the triangle using this formula

A=\frac{bh}{2}

where b = base and h = height

The base (triangle) has a base length of 8 inches and a height of 6 inches

Having found the information we needed, we plug it into the formula

So

A=\frac{6*8}{2} \\6*8=48\\\frac{48}{2} =24\\A=24in^2

So the area of the base is 24 in²

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40x=10x^2+41 <br><br> Identify the number of solutions and their types using the discriminant
nydimaria [60]

Number of solutions: no roots

Type of solution: Not Real

Step-by-step explanation:

We need to identify the number of solutions and their types using the discriminant.

We are given: 40x=10x^2+41\\

Rearranging:

40x-10x^2-41=0\\10x^2-40x+41=0

Discriminant can be found by: b^2-4ac

where b=-40, a=10 and c=41

Putting values:

b^2-4ac\\=(-40)^2-4(10)(41)\\=1600-1640\\=-40\\

So, Discriminant is -40

If the discriminant is less than zero i.e -40 then there are no real roots.

So, Number of solutions: no roots

Type of solution: Not Real

Keywords: discriminant

Learn more about discriminant at:

  • brainly.com/question/8196933
  • brainly.com/question/9328925
  • brainly.com/question/9184197

#learnwithBrainly

6 0
3 years ago
Linda goes water-skiing one sunny afternoon. After skiing for 15 min, she signals to the driver of the boat to take her back to
trasher [3.6K]
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2


abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.


d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
4 0
3 years ago
Find the perimeter of a regular octagon if one side has a measure of 8cm A) 16 cm B) 56cm C) 64cm D) 72cm
zysi [14]
C. 64cm 
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