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3 years ago

Plz help me with this homework i have

Mathematics

2 answers:

Archy [21]3 years ago

8 0

the answer is D i’m pretty sure

eduard3 years ago

7 0

i’m also pretty sure that it’s d, i’m not the best at it though but that’s the one i got

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Simplify 6 cm : 1.5 m

Zolol [24]

6cm=0.06m

0.06m : 1.5m

6m : 150m

1m : 35m

4 0

3 years ago

Find the transition matrix from B to B'. B = {(-1,2), (3, 4)), B' = {(1, 0), (0, 1)} STEP 1: Begin by forming the following matr

8_murik_8 [283]

Answer: The required matrix is

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

Step-by-step explanation: We are given to find the transition matrix from the bases B to B' as given below :

B = {(-1,2), (3, 4)) and B' = {(1, 0), (0, 1)}.

Let us consider two real numbers a, b such that

$(-1,2)=a(1,0)+b(0,1)\\\\\Rightarrow (-1,2)=(a,b)\\\\\Rightarrow a=-1,b=2.$

Again, let us consider reals c and d such that

$(3,4)=c(1,0)+d(0,1)\\\\\Rightarrow (3,4)=(c,d)\\\\\Rightarrow c=3,d=4.$

Therefore, the transition matrix is given by

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

Thus, the required matrix is

$T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .$

7 0

3 years ago

Lateral area of cylinder with r=4 h=5

yulyashka [42]

Answer:

formula: 2πrh

Step-by-step explanation:

2πrh= 2×π×4×5≈125.66371

3 0

3 years ago

PLS PLS I NEED HELP I HAVE NO TIME I'LL MARK YOU BRAINLIST !!!

Dominik [7]

Answer:

1) y = 5/2x - 3/2

2) y = 2/5x - 4/5

Step-by-step explanation:

(1, 1) and (3, 6)

m = (y2 - y1)/(x2 - x1)

m= (6 - 1)/(3-1)

m= 5/2

y - y1 = m(x - x1)

y - 1 = 5/2(x - 1)

y - 1 = 5/2x - 5/2

y = 5/2x - 3/2

(2, 0) and (7, 2)

m = (y2 - y1)/(x2 - x1)

m= (2 - 0)/(7 - 2)

m = 2/5

y - y1 = m(x - x1)

y - 0 = 2/5(x - 2)

y = 2/5x - 4/5

5 0

2 years ago

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The function h(x) is quadratic and h(3) = h(–10) = 0. Which could represent h(x)?

Lyrx [107]

I hope this helps you

6 0

3 years ago

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