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nika2105 [10]
3 years ago
7

Allison is working two summer jobs, making $12 per hour lifeguarding and $8 per hour washing cars. Last week Allison worked 3 mo

re hours lifeguarding than hours washing cars hours and earned a total of $96. Graphically solve a system of equations in order to determine the number of hours Allison worked lifeguarding last week, x , x, and the number of hours Allison worked washing cars last week, y y.

Mathematics
1 answer:
timama [110]3 years ago
3 0

Answer:

Allison worked 6 hours lifeguarding and 3 hours washing cars.

Step-by-step explanation:

Let

Number of hours Allison worked lifeguarding last week = x

Number of hours Allison worked washing cars last week = y

1. Last week Allison worked 3 more hours lifeguarding than hours washing cars hours, then

x-y=3

<u>Lifeguarding:</u>

$12 per hour

$12x in x hours.

<u>Washing cars:</u>

$8 pere hour

$8y in y hours.

2. Allison earned a total of $96, hence

12x+8y=96

You get the system of two equations:

\left\{\begin{array}{l}x-y=3\\ \\12x+8y=96\end{array}\right.

Plot the graphs of these two equations (see attached diagram). These line intersect at point (6,3), so Allison worked 6 hours lifeguarding and 3 hours washing cars.

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y is directly proportional to x^3. it is known that =5 for a particular value of x. find the value of y when this value of y whe
alina1380 [7]

Answer:

The value of y when the value of x is multiplied by \frac{1}{2} is \frac{5}{8}.

Step-by-step explanation:

According to the statement, we have the following relationship:

y = k\cdot x^{3} (1)

Where:

x - Independent variable.

y - Dependent variable.

k - Proportionality constant.

We can eliminate the proportionality constant by constructing the following relationship:

\frac{y_{2}}{y_{1}} = \left(\frac{x_{2}}{x_{1}} \right)^{3}

If we know that y_{1} = y, y_{2} = 5, x_{2} = x_{o} and x_{1} = \frac{1}{2}\cdot x_{o}, then the value of y when the value of x is multiplied by \frac{1}{2} is:

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2 years ago
PLEASE HELP ANSWER THESE QUESTIONS!
Sliva [168]

Answer:

Step-by-step explanation:

a² - b² = (a+ b)(a - b)

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=\frac{y^{2}-36}{y^{2}-49}*\frac{y-7}{y+6}\\\\=\frac{y^{2}-6^{2}}{y^{2}-7^{2}}*\frac{y-7}{y+6}\\\\=\frac{(y+6)*(y-6)}{(y+7)*(y-7)}*\frac{y-7}{y+6}\\\\=\frac{y-6}{y+7}\\

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Hint :  m² - 7m - 8

sum = -7

Product  = -8

Factor = (-8), 1

m² - 7m - 8  =m² - 8m + m - 8

                   = m*(m - 8) + (m-8)

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Answer:

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