The probability that a student is a female or major in civil engineering is 62%
<h3>How to determine the probability?</h3>
Let A represent Female and B represents civil engineering.
So, we have:
P(A) = 49%
P(B) = 21%
P(A and B) = 8%
The required probability is calculated as:
P(A or B) = P(A) + P(B) - P(A and B)
This gives
P(A or B) = 49% + 21% - 8%
Evaluate
P(A or B) = 62%
Hence, the probability that a student is a female or major in civil engineering is 62%
<h3>Complete question</h3>
At a certain college, 49% of the students are female, and 21% of the students major in civil engineering. Furthermore, 8% of the students both are female and major in civil engineering. What is the probability that a randomly selected female student majors in civil engineering?
Read more about probability at:
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Answer:
1.86
Step-by-step explanation:
Answer:
9 x (6+x) = 1
Step-by-step explanation:
Hey there :)
We know the formula for simple interest is
I = prt
{ The picture includes what each stands for }
Lehena:Initial amount = $100
Interest rate = 2.5% =

Time = 3 years
I = ( 100 )( 0.025 )( 3 )
= 7.5$
Total = $100 + $7.5 =
$107.5Marty:Initial amount = $100
Interest rate = 2% =

Time = 3 years
I = ( 100 )( 0.02 )( 3 )
= $6
Total = $100 + $6 =
$106How much more than Marty did Lehena receive?= Total Amount of Lehena - Total Amount of Marty
= 107.5 - 106
= $1.5Your answer will be option
B) $1.50