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s344n2d4d5 [400]
3 years ago
6

Find the area of this shape ​

Mathematics
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

40 ft squared

Step-by-step explanation:

On the top right corner cut the shape and you will have a length of 4 ft and width of 2 ft. 4ft x 2ft = 8ft squared. Now your other shape at the bottom which would be a  big rectangle has a width of 8ft and a length of 4ft. 8ft x 4ft = 32 ft squared. Now 8ft squared + 32 ft squared = 40 ft squared that would be its area.

allsm [11]3 years ago
7 0

Answer:

36 ft²

Step-by-step explanation:

Area = 4 × 4 + 6 × 4

Area = 16 + 20

Area = 36 ft²

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100 POINTS PLUS BRAINLIST
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5 0
3 years ago
What is 128/23 i want you to explain the most complex way as you can!
Alborosie

Divide the fraction gives you an irrational number since the decimal goes on forever but since the decimal can be written as a "fraction or ratio" it is rational.

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4 0
3 years ago
Read 2 more answers
Select the function that's represented in the graph. Question 5 options: A) ƒ(x) = x2 – 3 B) ƒ(x) = –1∕2x2 – 3 C) ƒ(x) = –x2 – 3
Neporo4naja [7]

Answer:

a)

Step-by-step explanation:

hello,

because of the end behaviour the constant in  x^2 should be positive so we have a) or d)

f(0)=-3 in both cases

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x^2-3=(x-\sqrt{3})(x+\sqrt{3})

so f(x)=0 for x=\sqrt{3} \ or \  x = -\sqrt{3}

so the correct answer is A)

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3 0
3 years ago
A taxi driver charges a fixed rate of r to pick up a passenger. In addition, the taxi driver charges a rate of m for each mile d
aivan3 [116]
T= MN+R
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8 0
3 years ago
On a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24
Helen [10]

Answer:

30.06 degree Celsius at 4:00 PM.

Step-by-step explanation:

We have been given that on a hot Saturday morning while people are working​ inside, the air conditioner keeps the temperature inside the building at 24 degrees C. At noon the air conditioner is turned​ off, and the people go home. The temperature outside is a constant 35 degrees C for the rest of the afternoon. The time constant for the building is 5 ​hr. We are asked to find the temperature inside the building at 4:00 PM.

We will use Newton's law of cooling to solve our given problem.

T(t)=M_0+(T_0-M_0)e^{-kt}, where

T(t) = Temperature after t hours.

M_0 = Temperature of surrounding environment,

k = Time constant.

\frac{1}{k}=5\Rightarrow k=\frac{1}{5}

Upon substituting our given values in Newton's cooling law, we will get:

T(t)=35+(24-35)e^{-\frac{t}{5}}

T(t)=35-11e^{-\frac{t}{5}}

To find the temperature at 4:00 pm, we will substitute t=4 in our formula as:

T(4)=35-11e^{-\frac{4}{5}}

T(4)=35-\frac{11}{e^{\frac{4}{5}}}

T(4)=35-\frac{11}{2.2255409284924674}

T(4)=35-4.9426186052894379601

T(4)=30.05738139471

T(4)\approx 30.06

Therefore, the temperature inside building would be approximately 30.06 degree Celsius at 4:00 PM.

5 0
3 years ago
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