Question

Use the Quadratic Formula to solve for x and then determine whether your solution is real or

Answer 1

Answer:

$x = -2$   or   $x= -3$

The solution is real.

Step-by-step explanation:

x^2 + 5x + 6 = 0

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$x = \dfrac{-5 \pm \sqrt{5^2 - 4(1)(6)}}{2(1)}$

$x = \dfrac{-5 \pm \sqrt{25 - 24}}{2}$

$x = \dfrac{-5 \pm \sqrt{1}}{2}$

$x = \dfrac{-4}{2}$  or  $x = \dfrac{-6}{2}$

$x = -2$   or   $x= -3$

The solution is real.