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3 years ago

a giraffe can run up to 46.93 feet per second. how far can a giraffe run in 1.8 seconds. justify your answer

Mathematics

2 answers:

mel-nik [20]3 years ago

6 0

1. 46.93 ft/1 sec = x ft/ 1.8 sec
2. cross multiply
3. 1x= 84.474
4. x= 84.474 ft

Snowcat [4.5K]3 years ago

3 0

Answer:

Therefore, 84.476 feet

Step-by-step explanation:

Given : giraffe can run up to 46.93 feet per second.

To find : how far can a giraffe run in 1.8 seconds.

Solution : We have given

giraffe can run up in 1 second = 46.93 feet

giraffe can run up in 1.8 second = 46 .93 * 1.8

giraffe can run up in 1.8 second = 84.476 feet

Therefore, 84.476 feet

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The option that proves PQ = LO is (a)

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$\mathbf{M = (3,0)}$

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$\mathbf{O = (0,7)}$

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So, we have:

$\mathbf{P = \frac{LM}{2}}$

$\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}$

$\mathbf{P = (\frac{3}{2},0)}$

Q is the midpoint of NO.

So, we have:

$\mathbf{Q = \frac{NO}{2}}$

$\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}$

$\mathbf{Q = (\frac{3}{2},7)}$

Distance PQ is calculated as follows:

$\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

This gives:

$\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}$

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$\mathbf{PQ = 7}$

Distance LO is calculated as follows:

$\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}$

$\mathbf{LO = \sqrt{ 7^2}}$

$\mathbf{LO=7}$

So, we have:

$\mathbf{PQ = 7}$

$\mathbf{LO=7}$

Thus:

$\mathbf{PQ = LO}$

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

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3 years ago

Read 2 more answers

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