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2 years ago

9

Please help, my brain just sucks rn. The area of a rectangle is 93.6 square inches. If the length of one of its sides is 5.2 in.

what is its perimeter?

1 answer:

snow_tiger [21]2 years ago

3 0

46.4 inch

Step-by-step explanation:

Area=l×b

93.6 =5.2×b

93.6/5.2 =b

So b= 18

Again,

p=2(l+b)

p=2(18+5.2)

p= 2×23.2

p=46.4

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2 years ago

Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Yakvenalex [24]

Answer:

$\sin d = \frac{4}{7}$ ; $\sin e = \frac{\sqrt{33} }{7}$

$\cos d = \frac{\sqrt{33} }{7}$ ; $\cos e = \frac{4}{7}$

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Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

$\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

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__________________________________________________

According to the question ,

1) When α (alpha) = d

$\sin d = \frac{4}{7}$

$\cos d = \frac{\sqrt{33} }{7}$

$\tan d = \frac{4}{\sqrt{33} }$

2) When α (alpha) = e

$\sin e = \frac{\sqrt{33} }{7}$

$\cos e = \frac{4}{7}$

$\tan e = \frac{\sqrt{33} }{4}$

3 0

2 years ago