There are 525600 minutes in a regular year
There are 527040 minutes in a leap year
I hope that's help !
B. (6, -8)
First, you need to figure out the slope of the line
(y1 - y2) / (x1 - x2)
After substituting points D(-3, 4) A(3, -4)
[4 - (-4)] / (-3 - 3)
(8) / (-6)
The slope of the line is -8/6 or -4/3 simplified
Then you can put it in point slope form:
(y - y1) = m(x - x1)
(y - y1) = -4/3(x - x1)
The point that I am using for point slope form is A(3, -4)
[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)
Next you have to simplify the equation so that y is isolated
y + 4 = -4/3(x - 3)
First distribute the -4/3
y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4
Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x
Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal
For example) (6, -8)
-8 = -4/3(6)
-8 = -8
So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D
~~hope this helps~~
Answer:
the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.
Step-by-step explanation:
The variation of the concentration of salt can be expressed as:
being
C1: the concentration of salt in the inflow
Qi: the flow entering the tank
C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)
Qo: the flow going out of the tank.
With no salt in the inflow (C1=0), the equation can be reduced to
Rearranging the equation, it becomes
Integrating both sides
It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.
The final equation for the concentration of salt at any given time is
To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:
Answer:
x = 26/45
Step-by-step explanation:
