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2 years ago

Find the volume of the composite solid. Round your answer to the nearest tenth.

Mathematics

1 answer:

amm18122 years ago

4 0

Answer:

Volume of the Figure $=825.38m^3$

Step-by-step explanation:

Volume of the figure = Volume of the Upper cone+Volume of the lower cone

Volume of a cone = $\pi *r^2*\frac{h}{3}$

Volume of the Upper Cone with

$height=12m$

$radius=6m$

$3.14*6*6*\frac{12}{3}$

$=3.14*6*6*4\\\\=3.14*36*4\\\\=3.14*144\\\\=147.14m^3$

Volume of the Lower cone with $radius=6m$ and $height=18m$

$=3.14*6*6*\frac{18}{3} \\\\=3.14*6*6*6\\\\=3.14*36*6\\\\=3.14*216\\\\=678.24m^3$

Volume of the Whole Figure = $147.14+678.24$

Volume of the Figure $=825.38m^3$

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3 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

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g(x) = y = x

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x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

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We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

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2 years ago

In need of help of these math questions

vitfil [10]

Answer:

1. 4

2. 6.4

3. 10.0828313253

Explanation:

15/12=1.25

8/1.25=6.4

3. ill write explanation for 3 later im occupied those are the correct answers

problably they want you to round to nearest tenth

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2 years ago

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3 years ago

There are four movies showing at the theater, 2/5 of the people bought tickets for the comedy, 1/4 bought tickets for the horror

RUDIKE [14]

Given:

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Number of people bought tickets for horror = $\frac{1}{4}$

Number of people bought tickets for kids movie = $\frac{3}{10}$

To find the number of people who bought tickets for the action movie.

Let us take,

Total number of tickets = 1

Now,

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So,

$(\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )$

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= $\frac{19}{20}$

Rest are action movie's tickets.

Therefore,

Number of action movie tickets = $1-\frac{19}{20}$

= $\frac{20-19}{20}$

= $\frac{1}{20}$

Hence,

The number of people who bought the tickets for action movie is $\frac{1}{20}$ .

7 0

3 years ago

Find the volume of the composite solid. Round your answer to the nearest tenth.​

Find the volume of the composite solid. Round your answer to the nearest tenth.