A cell with 2cm sides has a surface area of 6 × a2 or <span> a</span>2<span> + a</span>2<span> + a</span>2<span> + a</span>2<span> + a</span>2<span> + a</span><span>2
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Answer:
if those functions under the radical are multiplied together they can be expanded as:
I=((x1+x2)^2 - 1)*(1-(x1-x2)^2)/8
let u=x1+x2 and v=x1-x2
I = (u ^ 2–1) * (1-v ^ 2)
du = dx1 + dx2; dv = dx1-dx2;
dx1 * dx2 = (du-dx2) * (dx1-dv)
or-or-or ...
int(I)*dx1*dx2=5/2
Step-by-step explanation:
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11. 5.63 | 56.3 | 563. 14. 10^2 | 4.2 | 42
Answer:
3
Step-by-step explanation:
