Find the equation of the line. A line that is perpendicular to the graph of 3x +2y =6 and contains the point (6,-3)
1 answer:
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Step-by-step explanation:
We have been given an equation y+6=45(x+3) in point slope form.
It says to use the point and slope from given equation to create the graph.
So compare equation y+6=45(x+3) with point slope formula
y-y1=m(x-x1)
we see that m=45, x1=-3 and y1=-6
Hence first point is at (-3,-6)
slope m=45 is positive so to find another point, previous point will move 45 units up then 1 unit right and reach at the location (-2,39).
Now we just graph both points (-3,-6) and (-2,39) and join them by a straight line. Final graph will look like the attached graph.
