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alexandr1967 [171]
3 years ago
7

Find the equation of the line. A line that is perpendicular to the graph of 3x +2y =6 and contains the point (6,-3)

Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0
Answer:

y = 2/3x

Step-by-step explanation:

3x + 2y = 6

2y = 6 - 3x

y = 3 - 3x/2 or y = - 3/2x + 3

- - - - - - - - - - - - - -
Then find the negative reciprocal of the slope of the original line.

y = 2/3x
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Answer:

i)

  • <em>DA is diameter and AX is tangent to circle</em>

<u>Your answer is correct</u>

  • m∠ABD = 90°, m∠DAX = 90°

ii)

<u>Given m∠BAX = 42° and ∠DAB is complementary with BAX ⇒ </u>

  • m∠DAB = 90° - 42° = 48°

<u>DC = BC ⇒ intercepted arcs are same ⇒ </u>

  • ∠CDB = ∠BDC

<u>mDC = mCB ⇒ mDCB = ∠DAB = 48° ⇒ </u>

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iii)

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<u>∠CBA is supplementary with ∠ADC as opposite angles of cyclic quadrilateral (∠ADB = ∠BAX = 42°)</u>

  • m∠ADC = m∠ADB  + m∠CDB = 42° + 24° = 68°
  • m∠CBA = 180° - m∠ADC = 180° - 68° = 112°

∠BAE

EA║CB and AB is transversal ⇒ CBA and BAE are supplementary angles:

  • m∠BAE = 180° - 112° = 68°

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  • ∠DCE = ∠DCB - ∠BCE
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  • ∠DCE = 132° - 112° = 20°
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Answer:

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Step-by-step explanation:

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I think this is correct but I'm not sure.

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What is the value of x in the equation?
Firlakuza [10]

Answer:

The answer is -2 1/6 because it the only on that works.

Step-by-step explanation:

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A
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