Answer:
first one: yes
second one: yes
third one: no
fourth one: yes
Step-by-step explanation:
From the second equation ,we can know that y=3.25x+0.75
plug it into the first equation
-4.5x-2(3.25x+0.75)=-12.5
-4.5x-6.5x-1.5=-12.5
-11x=-11
x=1
plug it back into the second equation, y=3.25x+0.75=4
the answer would be (1,4)
Answer:
It shifted 6 units down
Step-by-step explanation:
Do the graph normally without the k and compare them side by side.
The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.

Use the formula: (a+b)(a-b) = a^2 - b^2
![x^4 - [(x^2)^2 - 1^2]\\\\x^4 - (x^4-1)\\\\x^4 - x^4 + 1\\\\\boxed{\bf{1}}](https://tex.z-dn.net/?f=x%5E4%20-%20%5B%28x%5E2%29%5E2%20-%201%5E2%5D%5C%5C%5C%5Cx%5E4%20-%20%28x%5E4-1%29%5C%5C%5C%5Cx%5E4%20-%20x%5E4%20%2B%201%5C%5C%5C%5C%5Cboxed%7B%5Cbf%7B1%7D%7D)
No matter what the value of 'x' is, the final answer will always be
1.