Left over is 456 minus total of A+B+C
456-334=122
C d are equal so 122/2=61
the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer: B
Step-by-step explanation:
It is one sided test of R-squared being zero versus being greater than zero.
These are the steps of the test.
1. State the null and alternative hypothesis: ...
2. Compute the test statistic: ...
3. Find a (1 - 0.05)×100% confidence interval for the test statistic. ...
4. Decide whether to accept or reject the null hypothesis: 5.991 ∉ [0, 2.28], so reject H 0 .
5. Determine the p-value.
It would be B. 120 you would usually round up but the closest one to 129.02083 is 130 and since there is no 130 it would be 120
Answer:
x=-5/11, y=-9/11. (-5/11, -9/11).
Step-by-step explanation:
3x+2y=-3
y=4x+1
---------------
3x+2(4x+1)=-3
3x+8x+2=-3
11x=-3-2
11x=-5
x=-5/11
y=4(-5/11)+1
y=-20/11+11/11
y=-9/11
