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Lina20 [59]
3 years ago
6

A 10-foot ladder is leaning against a tree. The bottom of the ladder is 4 feet away from the bottom of the tree. Approximately h

ow high up the tree does the top of the ladder reach?
A.2.4
B.6.0
C. 9.2
D. 10.8
Mathematics
1 answer:
Archy [21]3 years ago
5 0
C. 9.2 is your answer

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a

Step-by-step explanation:

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1. Three friends pooled their money to purchase a new game system that costs $298. One person
iragen [17]

Answer:

First person: $107

Second person: $98

Third person: $93

Step-by-step explanation:

Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.

With the information given in the exercise, you can set up the following equations:

Equation 1 → f+s+t=298

Equation 2 → s=f-9

Equation 3 → t=f-14

Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":

f+(f-9)+(f-14)=298\\\\3f-23=298\\\\f=\frac{321}{3}\\\\f=107

Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".

Therefore, you get:

s=107-9\\\\s=98\\\\\\t=107-14\\\\t=93

5 0
3 years ago
G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.
vova2212 [387]

Answer:

▢ $\overline{DG}$ ≅ $\overline{FG}$

▢ $\overline{DG}$ ≅ $\overline{BG}$

▢ $\overline{GE}$ bisects \displaystyle ∠DEF

▢ $\overline{GA}$ bisects \displaystyle ∠BAF

Step-by-step explanation:

As you can see, angles \displaystyle BAF and \displaystyle DEF form two half-kites, which you should know have <em>two</em><em> </em><em>pairs of</em><em> </em><em>congruent</em><em> </em><em>sides</em>, therefore segments \displaystyle GA and \displaystyle GE are what you call angle bisectours, which is why segments \displaystyle FG, \displaystyle DG, and \displaystyle BG are congruent.

I am joyous to assist you at any time.

4 0
3 years ago
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