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3 years ago

Which answer choice below correctly identifies the 202nd term in the sequence 5, 10, 15, 20, 25 …?

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

4 0

The 202nd term in the sequence is 1010.

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DanielleElmas [232]

Answer:

Add the area of the rectangle with the semicircle.

10x4 + 0.5(3.14)(25)

40+39.25

79.25

So the answer is C. 79.

Let me know if this helps!

4 0

2 years ago

Help me guys thx so much

navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

Step 1: Multiply

$(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\$

$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

$2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}$

$10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

6 0

3 years ago

Read 2 more answers

Look at the picture below// 50 points // please help:((

34kurt

A parabola is the locus of points equidistant from the focus and directrix. This means the distance from the green point is the same to the focus as it is to the directrix. The appropriate choice is ...

... B. 7

7 0

2 years ago

Read 2 more answers

What is the prime factorization of 81m 2 x 3?

N76 [4]

The answer to your question is 3^4 · m^2 · x^3

4 0

3 years ago

calculate gas mileage of car that drives 283 miles on 12.3 gallons of gas andround to nearest tenth of a mpg

Studentka2010 [4]

283 divided by 12.3 = 23.008 and rounded it will just be 23.

5 0

2 years ago